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Neko [114]
3 years ago
8

A person walks first at a constant speed of 5.40 m/s along a straight line from point to point and then back along the line from

to at a constant speed of 3.10 m/s. (a) What is her average speed over the entire trip
Physics
1 answer:
rosijanka [135]3 years ago
6 0

Answer: The average speed over the entire trip is 3.94 m/s

Explanation:

As we know : speed=\frac{distance}{time}

Let the distance of straight line from point to point be = d

Total distance covered = 2d

Time taken to cover the forward journey = \frac{d}{5.40}

Time taken to cover the backward journey = \frac{d}{3.10}

Total time for the journey = Time taken to cover the forward journey  + Time taken to cover the backward journey  = \frac{d}{5.40}+\frac{d}{3.10}

Average speed = \frac{\text {total distance}}{\text {total time}}=\frac{2d}{\frac{d}{5.40}+\frac{d}{3.10}}=3.94m/s

Thus  average speed over the entire trip is 3.94 m/s

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A bag of sugar weighs 3.50 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration isone-sixth
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Therefore the Inductance is 24.42\mu H

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