Answer:
The magnitude of angular acceleration is
.
Explanation:
Given that,
Initial angular velocity, 
When it switched off, it comes o rest, 
Number of revolution, 
We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :
So, the magnitude of angular acceleration is
. Hence, this is the required solution.
<span>The person is dragging
with a force of 58 lbs at an angle of 27 degrees relating to the ground. We
want to use cosine function to look for the horizontal force component. And
then we can compute for W = (Horizontal Force) x (Distance). We want the
horizontal force component since that is the component that is parallel to the
direction the cart is moving. </span><span>
(cos 27 degrees)(58 lbs) = 51.69 lbs (This is the horizontal
force component.)
W = (51.69 lbs) x (70 ft) = 3618.3 ft*lbs</span>
Answer:
100 miles North East.
Explanation:
Please see attached photo for diagram.
In the attached photo, X represents the magnitude of the total displacement of the train.
Thus, we can obtain the value of X by using the pythagoras theory as illustrated below:
X² = 80² + 60²
X² = 6400 + 3600
X² = 10000
Take the square root of both side
X = √10000
X = 100 miles.
Therefore, the magnitude of the total displacement of the train is 100 miles North East.
Math is the process of using the given information, along with
all the general stuff that you know, to find the missing information.
With no given information, we have no way to even guess at
an answer.