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FromTheMoon [43]
3 years ago
6

A bullet with a mass of 0.00658 kg is fired through a 1.95 kg block of wood on a frictionless surface. The initial speed of the

bullet is 822 m/s, and the speed of the bullet after it exits the block is 439 m/s. At what speed does the block move after the bullet passes through it?
Physics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

The final velocity of the block is 1.29 m/s

Explanation:

We can solve this problem by using the principle of conservation of momentum: in fact, the total momentum of the system must be conserved before and after the collision. Therefore, we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 0.00658 kg is the mass of the bullet

u_1 = 822 m/s is the initial velocity of the bullet

v_1 = 439 m/s is the final velocity of the bullet

m_2 = 1.95 kg is the mass of the block

u_2 = 0 is the initial velocity of the block

v_2 is the final velocity of the block

Re-arranging the equation and solving for v2, we find:

v_2 = \frac{m_1 u_1 - m_1 v_1}{m_2}=\frac{(0.00658)(822)-(0.00658)(439)}{1.95}=1.29 m/s

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

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