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4 years ago

A bowling ball traveling at the same constant speed is which one of newtons three laws?

1 answer:

7 0

If an object is traveling at the same constant speed AND
IN A STRAIGHT LINE, then it's demonstrating Newton's
1st and 2nd laws of motion.

If its speed or direction is changing, then it's demonstrating
Newton's 2nd law of motion.

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mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$

$v_e$ = 16 × $v_e_E$

Given that the escape velocity for Earth, $v_e_E$ ≈ 11,186 m/s, we have;

The escape velocity on the planet = $v_e$ ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0

3 years ago

Stewart (70 Kg) is attracted to Ms. Little (60 Kg) who sits 2 m away. What is the gravitational attraction between them? G=6.67×

ikadub [295]

Happy Holidays!

We can use the following equation to solve for the gravitational force:

$\large\boxed{F_g = G\frac{m_1m_2}{r^2}}$

Fg = force due to gravity (N)

G = Gravitational constant

m1,m2 = masses of the objects (kg)

r = distance between the objects (m)

Plug in the given values into the equation:

$F_g = (6.67*10^{-11})\frac{(70)(60)}{(2)^2}} = \boxed{7.0 * 10^{-8}N}$

7 0

3 years ago

Which involves more work in the scientific sense: moving the boxes and the furniture down from the second floor or up to the fif

Advocard [28]

Answer:

moving the boxes and the furniture up to the fifth floor.

Explanation:

The work done when moving an object up or down is equal to its change of gravitational potential energy:

$W=mg \Delta h$

where

m is the mass of the object

g is the gravitational acceleration

$\Delta h$ is the change in height of the object

We have two opposite situations:

1) when an object is moved upward, $\Delta h$ is positive, so the work done W is positive as well: this means that we need to do work in order to move the object, because we have to "win" the effect of gravity, which pulls the object downward

2) when an object is moved downward, $\Delta h$ is negative, so the work done W is negative as well: this means that we do not need to do work on the object, because it is already done by gravity, which pulls the object downward.

Therefore, more work is done when we are moving the boxes and the furniture up to the fifth floor.

8 0

3 years ago

the spring was compressed three times farther and then the block is released, the work done on the block by the spring as it acc

frosja888 [35]

Answer:

The work done on the block by the spring as it accelerates the block is 4kx².

Explanation:

Let initial distance is x.

It was compressed three times farther and then the block is released, new distance is 3x.

The work done in compressing the spring is given by :

$W=\dfrac{1}{2}k(x_2^2-x_1^2)$