You are riding a bicycle. You apply a forward force of 150 N, and you and the bicycle have a combined mass of 90 kg. What is the
1 answer:
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Answer:
40 ms¯².
Explanation:
To solve this problem, we shall illustrate the question with a diagram.
The attached photo gives a better understanding of the question.
From the attached photo:
Velocity (v) = 160 ms¯¹
Time (t) = 4 secs.
Acceleration (a) =?
Acceleration (a) = Velocity (v) /time (t)
a = v/t
a = 160/4
a = 40 ms¯²
Therefore, the initial acceleration of the rocket is 40 ms¯².
To solve the exercise it is necessary to apply the concepts related to Newton's Second Law, as well as the definition of Weight and Friction Force.
According to the problem there is a movement in the body and it is necessary to make a sum of forces on it, so that
There are two forces acting on the body, the Force that is pushing and the opposing force that is that of friction, that is
To find the required force then,
By definition we know that the friction force is equal to the multiplication between the friction coefficient and the weight, that is to say
Therefore the horizontal force applied on the block is B) 230N
Answer:
Approximately .
Explanation:
Make use of the fact that total momentum is conserved in collisions.
The momentum of an object of mass and velocity
is
.
The momentum of the two trolleys before the collision would be:
.
.
Thus, the total momentum of the two trolleys right before the collision would be .
Since the two trolleys are stuck to one another after the collision, they could modelled as one big trolley of mass .
The momentum of the two trolleys, combined, is conserved during the collision. Thus, the total momentum of the new trolley of mass would continue to be
shortly after the collision.
Rearrange the equation to find the velocity of the two trolleys combined:
.