If you create an equilibrium mixture from f e 3 and s c n − ions, adding c l − ions will choose. Highlight_off because choose. H
2 answers:
The chloride ions are not part of the ionic equilibrium, adding them to the solution will merely raise the concentration of anions.
<h3>What is equilibrium?</h3>When a chemical reaction does not convert all reactants to products, it reaches equilibrium. Many processes attain a state of balance, or dynamic equilibrium, in which both reactants and products are present.
The following is the ionic equilibrium between iron (III) ion+ and thiocyanate ions:
The addition of either ion in the ionic equilibrium will shift the equilibrium position to the left or right, according to the principle of equilibrium.
The inclusion of chloride ions, Cl-, which are not components of the ionic equilibrium, increases the levels of anions in the solution.
Thus, the chloride ions are not part of the ionic equilibrium, adding them to the solution will merely raise the concentration of anions.
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Since chloride ions are not part of the ionic equilibrium, addition of chloride ions will only increase the concentration of the anions in the solution.
<h3>What is ionic equilibrium?</h3>An ionic equilibrium is an equilibrium that exists between two or more ions in an aqueous solution.
The ionic equilibrium between iron (iii) ion and thiocyanate ions is given below:
From the principle of equilibrium, addition of either ions in the ionic equilibrium will alter equilibrium position to the left or right.
Addition of chloride ions, Cl- which is not a part of the ionic equilibrium will only increase the concentration of the anions in the solution.
Learn more about ionic equilibrium at: brainly.com/question/13879496
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Answer:
C) No work is required to move the negative charge from point A to point B.
Explanation:
An equipotential surface is defined as a surface connecting all the points at the same potential.
Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.
The work done when moving a charge is given by
where
q is the charge
is the potential difference between the initial and final point of motion of the charge
However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so
And so, the work done is also zero.
Expand each vector into their component forms:
Similarly,
Then assuming the resultant vector is the sum of these three vectors, we have
and so has magnitude
and direction such that