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Gwar [14]
2 years ago
8

If you create an equilibrium mixture from f e 3 and s c n − ions, adding c l − ions will choose. Highlight_off because choose. H

ighlight_off
Physics
2 answers:
schepotkina [342]2 years ago
7 0

The chloride ions are not part of the ionic equilibrium, adding them to the solution will merely raise the concentration of anions.

<h3>What is equilibrium?</h3>

When a chemical reaction does not convert all reactants to products, it reaches equilibrium. Many processes attain a state of balance, or dynamic equilibrium, in which both reactants and products are present.

The following is the ionic equilibrium between iron (III) ion+ and thiocyanate ions:

\rm Fe^{3+}  \rightleftharpoons SC \ N^{-}

The addition of either ion in the ionic equilibrium will shift the equilibrium position to the left or right, according to the principle of equilibrium.

The inclusion of chloride ions, Cl-, which are not components of the ionic equilibrium, increases the levels of anions in the solution.

Thus, the chloride ions are not part of the ionic equilibrium, adding them to the solution will merely raise the concentration of anions.

Learn more about the equilibrium here:

brainly.com/question/13458865

#SPJ4

Lunna [17]2 years ago
4 0

Since chloride ions are not part of the ionic equilibrium, addition of chloride ions will only increase the concentration of the anions in the solution.

<h3>What is ionic equilibrium?</h3>

An ionic equilibrium is an equilibrium that exists between two or more ions in an aqueous solution.

The ionic equilibrium between iron (iii) ion and thiocyanate ions is given below:

Fe^{3+}\rightleftharpoons SC \: N^{-}

From the principle of equilibrium, addition of either ions in the ionic equilibrium will alter equilibrium position to the left or right.

Addition of chloride ions, Cl- which is not a part of the ionic equilibrium will only increase the concentration of the anions in the solution.

Learn more about ionic equilibrium at: brainly.com/question/13879496

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Explanation:

From the question we are told that

   The  coefficient of static friction is  \mu_s  =  0.42

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=>   mg  *  \mu_s  =  ma

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