Saponification is the hydrolysis of fats or oils under basic conditions to afford glycerol and the salt of the corresponding fatty acid. ... It is important to the industrial user to know the amount of free fatty acid present, since this determines in large measure the refining loss.
Answer:
Temperature increase = ΔT = 2.08 °C
Explanation:
Given data:
Energy absorbed by plant = 4200 J
Specific heat capacity of soil = 0.84 J/g°C
Mass of soil = 2400 g
How much temperature increase = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
by putting values,
4200 J = 2400 g ×0.84 J/g°C × ΔT
4200 J = 2016 J/°C × ΔT
ΔT = 4200 J / 2016 J/°C
ΔT = 2.08 °C
Answer:
its answer A....that's the answer is
Explanation:
The visible light spectrum is the section of the electromagnetic radiation spectrum that is visible to the human eye. Essentially, that equates to the colors the human eye can see. It ranges in wavelength from approximately 400 nanometers (4 x 10 -7 m, which is violet) to 700 nm (7 x 10-7 m, which is red).
Answer:
wavelength (λ) = 2.73 E-4 m
frecuency (f) = 1.10 E12 s-1
Explanation:
Stefan-Boltzmann law:
- intensity of the radiation for a black body (W) = σ.(T)∧4
∴ σ = 5.670 E-8 W/m²(K)∧4
∴ T = 298 K
⇒ W = (5.670 E-8 W/m²K∧4)×(298 K)∧4
⇒ W = 447.145 W/m² = 447.145 J/s.m²
assuming an area of 1 m²
⇒ W = 447.145 J/s
Rayleigh-Jeans's law:
∴ Black body radiation at a specific wavelength (Bλ(T)):
⇒ Bλ(T) = ( 2 c.k.T ) / (λ)∧4
∴ c = 3 E8 m/s.....velocity of speed
∴ k = 1.38065 E -23 J/K.........Boltzmann's constant
∴ Bλ(T) = 447.145 J/s.m²
⇒ (λ)∧4 = ((2)(3 E8 m/s)(1.38065 E-23 J/K)(298 K)) / (447.145 J/s)
⇒ λ = (5.521 E-15)∧(1/4)
⇒ λ = 2.73 E-4 m
⇒ f = (3 E8 m/s) / (2.73 E-4 m)
⇒ f = 1.10 E12 s-1
We use a solution, such as a cabbage ph indicator, to measure the ph of household items :
- to test the safety of water
- to make sure conditions are safe
<h3>Cabbage ph indicator:</h3>
Anthocyanin, a water-soluble pigment found in red cabbage, can change color when combined with an acid or a basic. The color changes to red in situations with a pH under 7, and to bluish-green in alkaline (basic) environments with a pH above 7. Cabbage isn't known to cause acid reflux, but plenty of other common foods are.
Anthocyanin turns pink when it interacts with the hydronium ions in an acid, and blue or green when it interacts with the hydroxide ions in a base. Because it may inform us if a substance is acidic or basic by changing color, cabbage juice is referred to as a pH indicator.
Learn more about cabbage pH here:
brainly.com/question/9626174
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