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jekas [21]
2 years ago
11

A car starts from rest and travels for t1 seconds with a uniform acceleration a1. The driver then applies the brakes, causing a

uniform acceleration a2. If the brakes are applied for t2 seconds, determine the following. Answers are in terms of the variables a1, a2, t1, and t2. (a) How fast is the car going just before the beginning of the braking period?
Physics
1 answer:
Triss [41]2 years ago
5 0

Explanation:

It is given that,

Initially the car is at rest and travels for t₁ seconds with a uniform acceleration a₁. The driver then applies the brakes, causing a uniform acceleration a₂, If the brakes are applied for t₂ seconds.

We need to find the speed of the car just before the beginning of the braking period.

Using the formula of acceleration. It is given by :

a_1=\dfrac{v-u}{t_1}

u = 0

v=a_1\times t_1

So, just before the beginning of the braking period the speed of the car is a_1\times t_1. Hence, this is the required solution.

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yanalaym [24]
Convex.

Concave curved inward (like how a cave foes in) and convex curves outward. Reflected and refracted do not apply to a lens.
3 0
3 years ago
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A monochromatic light beam is incident on a barium target that has a work function of 2.50 \mathrm{eV} . If a potential differen
leva [86]

The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).

  • Work function is a material property defined as the minimum amount of energy  required to infinitely remove electrons from the surface of a particular solid.
  • The potential difference required to support all emitted electrons is called the stopping potential which is given by v_0=\frac{K.E_m_a_x}{e} .....(1)
  • where v_0 is the stopping potential and e is the charge of the electron given by 1.6\times10^-^1^9 .

It is given that work function (Ф) of monochromatic light is 2.50 eV.

Einstein photoelectric equation  is given by:

K.E_m_a_x=E-\phi      ....(2)

where K.E(max) is the maximum kinetic energy.

Substituting (1) into (2) , we get

  ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV

As we know that E=\frac{hc}{\lambda}  ....(3)

where Speed of light,c = 3\times10^8 m/s and Planck's constant , h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs

From equation (3) , we get

\lambda=\frac{hc}{E} \\\\\lambda=\frac{  4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm

Learn about more einstein photoelectric equation  here:

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8 0
1 year ago
What is the momentum of a 72 kg baseball player who slides into home plate
Alina [70]

Answer:

B) 350 kg m/s

Explanation:

momentum or p is given by the equation p= mxv

We have the mass and velocity so we can use the equation directly

p= 72kg x 4.9 m/s

p= 352.8 kg m/s

4 0
2 years ago
Ca anyone help me with writing a lab report about the reaction between the pepper and the soap in water
7nadin3 [17]

Answer:

Buoyancy force and surface tension are the reactions that take places between soap and pepper experiment.

Explanation:

Surface tension:

The surface tension of a liquid is the tendency of liquid surfaces to resist an external force due to the cohesive nature of its molecules.

The pepper and soap experiment helps you to understand buoyancy force and surface tension.

Reaction between the pepper and soap is as following.

  • The pepper flakes float because of buoyancy force. It makes the pepper flakes to move away to the edge of the plate.
  • This happens because the liquid dish soap changes the surface tension of water.
  • And The pepper flakes are so light, it floats on the water surface due to surface tension.
  • when we add soap, it breaks the surface tension of water, but the water resists it. So they pull away from the soap along with the pepper flakes.
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This is the reaction that take places between soap and pepper experiment.

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6 0
1 year ago
Which term describes the difference in electrical charge across a membrane? View Available Hint(s) Which term describes the diff
Zinaida [17]

Answer:

Membrane potential

Explanation:

Membrane potential is describes the difference in electrical charge across a membrane.                                                                                                              

The difference in potential between exterior  and  interior of the  biological cell is known as Membrane potential.Generally it is denoted by  millivolts like mV and varies from -80 V to -40 V.

So the answer is Membrane potential

4 0
3 years ago
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