<u>Answer:</u>
<em>The amount of energy needed when water at 72 degrees c freezes completely at 0 degrees c is Joules</em>
<em></em>
<u>Explanation:</u>
where
= Final T - Initial T
=30125J
Q is the heat energy in Joules
c is the specific heat capacity (for water 1.0 cal/(g℃)) or 4.184 J/(g℃)
m is the mass of water
mass of water is assumed as 100 g (since not mentioned)
is the heat energy required for the phase change
=mass × heat of fusion
Total heat =
Total Heat = 30123J + 33600J
= 63725 J
= Joules is the answer
Answer:
The tabulated values at 120 C of <u><em>hfg = 2202.1</em></u><u> kJ/Kg </u>and <u><em>sfg </em></u><u>= 5.6 </u>
<u>kJ/Kg.K</u>
Explanation:
According to Clapeyron Equation :
Taking P2 at temperature 125 and P1 at 115 degree Celsius .
T = 120 + 273.15 = 393.15 K
P2 = 232.23 kPa and P1 = 169.18kPa
(these are experimental values given in the Data)
= 5.6131 kJ/Kg.K
The tabulated values at 120 C of <em>hfg = 2202.1</em> kJ/Kg and <em>sfg </em>= 5.6131
kJ/Kg.K
Answer:
I think the answer is A!!!
The answer is A bc if u do those steps you will find the answer.
Answer: The value of the equilibrium constant is 0.000023.
Explanation:
Equilibrium concentration of =
Equilibrium concentration of =
Equilibrium concentration of =
Equilibrium concentration of =
The given balanced equilibrium reaction is,
The expression for equilibrium constant for this reaction will be,
Thus the value of the equilibrium constant is 0.000023.