Density = mass / volume
D = 550 / 25
D = 22 g/mL
hope this helps!
Answer:
The advantages described below
Explanation:
Advantages of a balanced chemical equation versus word equation:
- easier to read: chemical equations typically only take one line and they include all the relevant information needed. They are short-hand notations for what we describe in words.
- balanced chemical equations show molar ratio in which reactants react and the molar ratio of the products. Those are coefficients in front of the species. This is typically not included in a word equation, for example, hydrochloric acid reacts with potassium hydroxide. The latter statement doesn't describe the molar ratio and stoichiometry.
- includes relevant information, such as catalysts, temperature and pressure above the arrow in the equation. We wouldn't have this in a word equation most of the time.
- shows the stoichiometry of each compound itself, e. g. if we state 'ammonia', we don't know what atoms it consists of as opposed to
. - includes states of matter: aqueous, liquid, gas, solid. This would often be included in a word equation, however.
You are exposed to nuclear radiation every day is true!
Answer:
not capable of being imagined or grasped mentally; unbelievable.
Explanation:
not capable of being imagined or grasped mentally; unbelievable.
You would need to utilize Mole ratios found in the adjusted condition;
for each mole of hydrogen utilized, 2 moles of HCl are delivered.
Thusly:
10 mol H2 x 2 mol HCl/1 mol H2 = 20 mol HCL.
For the second question:
you would need to change over 2.0x10^23 particles of Oxygen to moles of oxygen, utilizing Avogadro's number:
2.0x10^23 particles oxygen x 1 mol oxygen/6.022x10^23 atoms oxygen = 0.33 mol Oxygen
utilizing mole proportions once more:
0.66 mol H2O = 2 mol H2O/1 mol Oxygen x 0.33 mol Oxygen
45.0 mol H2O = 2 mol H2O/1 mol Oxygen x 22.5 mol Oxygen
fundamentally to answer stoichiometry, you should take a gander at the adjusted condition to make sense of the mole proportions between components/mixes, and utilizing mole proportions you can change over from moles of one component/compound to moles of another component/compound