carbon dioxide, that is what I found
Answer is: 25.84 milliliters of sodium metal.
Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.
d(Na) = 0.97 g/mL; density of sodim.
m(NaOH) = 43.6 g; mass of sodium hydroxide.
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 43.6 g ÷ 40 g/mol.
n(NaOH) =1.09 mol; amount of sodium hydroxide.
From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).
n(Na) = 1.09 mol.
m(Na) = 1.09 mol · 23 g/mol.
m(Na) = 25.07 g; mass of sodium.
V(Na) = m(Na) ÷ d(Na).
V(Na) = 25.07 g ÷ 0.97 g/mL.
V(Na) = 25.84 mL.
We all die. That's the end of that folks
Answer: The mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is
kg.
Explanation:
We know that relation between heat energy and specific heat is as follows.
q = 
As density of water is 1 kg/L and volume is given as 400,000 L. Therefore, mass of water is as follows.
Mass of water = Volume × Density
= 
= 400,000 kg
or, =
g (as 1 kg = 1000 g)
Specific heat of water is 4.2 J/gm K. Therefore, change in temperature is as follows.
= 305 K - 273 K
= 32 K
Now, putting the given values into the above formula and calculate the heat energy as follows.
q =
= 
=
J
or, =
kJ
According to the enthalpy of melting of ice 333 kJ/Kg of energy absorbed by by 1 kg of ice. Hence, mass required to absorb energy of
kJ is calculated as follows.
Mass = 
=
kg
Thus, we can conclude that the mass of ice you would need to add to bring the equilibrium temperature of the system to 300 K is
kg.
relative humidity is a measure of how much water an air mass at a given temperature can hold.
<u>Explanation:</u>
When a quantity of air at a supplied temperature exists the highest volume of water vapor, the air is considered to be saturated. The relative humidity is the water-vapor content of the air corresponding to its content at fullness.
Relative humidity can be described as the quantity of water vapor in air at a provided temperature related to what that air could endure at that temperature. We can thus adjust the relative humidity of an air bundle by either raising or lowering the volume of water vapor in the parcel OR by boosting or reducing the temperature of the air mass.