Answer:
Total cost = $40.25 (Approx)
Explanation:
Given:
Per ounce = $1.15
Number of student = 28
Each student eat = 0.035 kg
Find:
Total cost
Computation:
Total weight of candy = 28 × 0.035 kg
Total weight of candy = 0.98 kg
1 ounce = 0.028 kg (approx).
Total weight of candy = 0.98 kg / 0.028
Total weight of candy = 35 ounce (Approx)
Total cost = 35 × $1.15
Total cost = $40.25 (Approx)
Answer:
D) contains more OH– ions than H+ ions
Explanation:
THESE ARE THE OPTIONS FOR THE QUESTION
A) causes some indicators to change color B) conducts electricity C) contains more H+ ions than OH– ions D) contains more OH– ions than H+ ions
Base can be regarded as substance which can dissociates in water then form hydroxide ions (OH–) .
Bases can be regarded as compounds which break into hydroxide ions I.e (OH-) with more other compounds if put in an aqueous solution. Hence it contains more OH– ions
I think it goes like this.
mass = 78.6 g
molar mass = 60.1 g/mol
amount (in mols) = mass/mol
78.6 g / 60.1 g/mol = 1.30782 mol
^^rounded to 3 sig figs, final answer = 1.31mol
Answer:
a) dissolving sugar in water to form a mixture of sugar and water
Explanation:
exothermic reaction is reaction in which is heat is released during the reaction and endothermic reaction is a reaction in which heat is needed or required for the reaction to take place
all the options excluding option A) is exothermic as during the process of formation of bonds in oxidation, heat is released. rusting too is a slow form of oxidation and thus an exothermic reaction.
dissolving sugar in water is not exothermic reaction because their is no heat released. the sugar molecules simply disperses in the water molecules and form a solution.
Answer is: 25.84 milliliters of sodium metal.
Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.
d(Na) = 0.97 g/mL; density of sodim.
m(NaOH) = 43.6 g; mass of sodium hydroxide.
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 43.6 g ÷ 40 g/mol.
n(NaOH) =1.09 mol; amount of sodium hydroxide.
From chemical reaction: n(NaOH) : n(Na) = 2 : 2 (1: 1).
n(Na) = 1.09 mol.
m(Na) = 1.09 mol · 23 g/mol.
m(Na) = 25.07 g; mass of sodium.
V(Na) = m(Na) ÷ d(Na).
V(Na) = 25.07 g ÷ 0.97 g/mL.
V(Na) = 25.84 mL.