Answer:
6.022x10^23
Explanation:
Avogrado's number proved that one mole is equal to 6.022x10^23.
Answer:
A. Bar graph
Explanation:
Bar graphs are used to compare things between different groups or to track changes over time.
Answer:
3.51 g of oxygen per gram of gasoline is required.
Explanation:
Solution:
First of all we will write the balance chemical equation.
C8H18 + 12.5O2 → 8CO2 + 9H2O
This equation shows that,
1 mole of gasoline react with 12.5 mole of oxygen for complete burning.
mass of one mole of gasoline = 8×12 + 18×1 = 114 g
mass of 12.5 mole of oxygen = 12.5 (16×2) = 400 g
Formula:
mass of oxygen per gram of gasoline = (400 / 114) = 3.51
so, 3.51 g of oxygen require for per gram of gasoline.
Answer:
4th Option
Explanation:
HNO3 is an acid, KOH is a base and they react to produce KNO3 which is a salt and H2O water.
So this reaction is a neutralisation reaction.
The conversion between mm mercury to pascals is (1 mmHg)/(133.32 pascals).
Therefore, we use the conversion:
4.579 mmHg * (133.32 pascals/1 mmHg) = 610.5 pascals