Are usually solid shiny and conductive object

Following intense exercise, the blood pH was determined to be 7.1. If the HCO3- is 7.5mM and the pKa for HCO3- is 6.1, what is t

shusha [124]

Answer:

$0.75\ \text{mM}$

Explanation:

Concentration of $HCO_3^-$ = $[HCO_3^-]=7.5\ \text{mM}$

$pK_a$ for $HCO_3^-$ = 6.1

$pH$ of blood = 7.1

The reaction is as follows

$H_2CO_3+H_2O\rightarrow HCO_3^-+H_3O^+$

From the Henderson equation we get

$pH=pK_a+\log\dfrac{[HCO_3^-]}{[H_2CO_3]}\\\Rightarrow 7.1=6.1+\log \dfrac{7.5}{[H_2CO_3]}\\\Rightarrow 1=\log\dfrac{7.5}{[H_2CO_3]}\\\Rightarrow 10^1=\dfrac{7.5}{[H_2CO_3]}\\\Rightarrow [H_2CO_3]=\dfrac{7.5}{10}\\\Rightarrow [H_2CO_3]=0.75\ \text{mM}$

$CO_2(g)+H_2O(l)\rightarrow H_2CO_3(aq)$

Concentration of $H_2CO_3$ , $[H_2CO_3]=[CO_2]$

Concentration of $CO_2$ , $[CO_2]=[H_2CO_3]=0.75\ \text{mM}$ .

8 0

3 years ago

Convert 125m^3 to km^3

Ugo [173]

Answer:

1.25e-7

Explanation:

4 0

3 years ago

Three compounds that contain elements from Group 16 are SeO2F2 , SeOF2,

egoroff_w [7]

Answer:

A

Explanation:

A formal charge (FC) is the charge assigned to an atom in a molecule, assuming that electrons in all chemical bonds are shared equally between atoms, regardless of relative electronegativity(Wikipedia).

The formal charge on an atom in a molecule reflects the electron count associated with the atom compared to the isolated neutral atom(University of Calgary).

Looking at all the structures listed A-E for SeO2F2, only structure A minimizes the formal charges for each atom in SeO2F2.

4 0

3 years ago

3NO2(g) + H2O(l) — 2HNO3(aq) + NO(g)

antiseptic1488 [7]

Answer:

A. 3.65 g of H2O.

B. 26.33 g of NO.

C. 7.53 g of HNO3.

Explanation:

The balanced equation for the reaction is given below:

3NO2(g) + H2O(l) —> 2HNO3(aq) + NO(g)

Next, we shall determine the masses of NO2 and H2O that reacted and the masses of HNO3 and NO produced from the balanced equation.

This is illustrated below:

Molar mass of NO2 = 14 + (16x2) = 46 g/mol

Mass of NO2 from the balanced equation = 3 x 46 = 138 g

Molar mass of H2O = (2x1) + 16 = 18 g/mol

Mass of H2O from the balanced equation = 1 x 18 = 18 g

Molar mass of HNO3 = 1 + 14 + (16x3) = 63 g/mol

Mass of HNO3 from the balanced equation = 2 x 63 = 126 g.

Molar mass of NO = 14 + 16 = 30 g/mol

Mass of NO from the balanced equation = 1 x 30 = 30 g.

Summary:

From the balanced equation above,

138g of NO2 reacted with 18 g of H2O to produce 126 g of HNO3 and 30 g of NO.

A. Determination of the mass of H2O required to react with 28.0 g

of NO2.

This is illustrated below:

From the balanced equation above,

138g of NO2 reacted with 18 g of H2O.

Therefore, 28 g if NO2 will react with = (28 x 18)/138 = 3.65 g of H2O.

Therefore, 3.65 g of H2O is needed for the reaction.

B. Determination of the mass of NO produced from 15.8 g of H2O.

This is illustrated below:

From the balanced equation above,

18 g of H2O reacted to produce 30 g of NO.

Therefore, 15.8 g of H2O will react to produce = (15.8 x 30)/18 = 26.33 g of NO.

Therefore, 26.33 g of NO were produced from the reaction.

C. Determination of the mass of HNO3 produced from 8.25 g of NO2.

This is illustrated below:

From the balanced equation above,

138g of NO2 reacted to produce 126 g of HNO3.

Therefore, 8.25 g of NO2 will react to produce = (8.25 x 126)/138 = 7.53 g of HNO3.

Therefore, 7.53 g of HNO3 were produced from the reaction.

7 0

3 years ago

How do freeze-thaw cycles cause weathering?

natta225 [31]

Answer:

A. When water moves into a crack and freezes, it expands and forces the crack wider.

Explanation:

A crack in a rock can fill with water which then freezes as the temperature drops. As the ice expands, it pushes the crack apart, making the crack larger. When the temperature rises again, the ice melts, and the water fills the newer parts of the crack. Once the water freezes again when the temperature drops, the expansion of the ice causes further expansion to the crack.

8 0

3 years ago