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3 years ago

Are usually solid shiny and conductive object

Chemistry

1 answer:

crimeas [40]3 years ago

8 0

If the solid is a metal, yes. Most solids on the periodic table are metals

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How do birth and death rates affect a population size?

yawa3891 [41]

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When the death rate is higher than the birth rate, the population decreases. It increases when the opposite happens.

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2 years ago

This is an underground level where the ground becomes saturated with water.

ozzi

Answer: Pumping can affect the level of the water table. In an aquifer, the soil and rock is saturated with water.

Explanation:

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2 years ago

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Complete the equation for the reaction of sulfuric acid and sugar (sucrose). C12H22O11 + 11 H2SO4 ? 12 + 11 H2SO4 + 11

serg [7]

Answer :

The complete equation for the reaction of sulfuric acid and sugar is,

$C_{12}H_{22}O_{11}+11 H_2SO_4\rightarrow 12C+11H_2SO_4+11H_2O$

By the stoichiometry of the reaction,

1 mole of sucrose react with the 11 moles of sulfuric acid to give 12 moles of carbon and 11 moles of water.

In this reaction, sulfuric acid react with sucrose (sugar). It dehydrates the sugar molecules which means it eliminates the water.

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2 years ago

Determine the electron geometry (eg) and molecular geometry (mg) of <img src="https://tex.z-dn.net/?f=CH_3%5E%2B" id="TexFormula

Yuri [45]

Answer : The correct option is, (e) eg = trigonal planar, mg = trigonal planar

Explanation :

Formula used :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

The given molecule is, $CH_3^+$

$\text{Number of electron pair}=\frac{1}{2}\times [4+3-1]=3$

That means,

Bond pair = 3

Lone pair = 0

The number of electron pair are 3 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

Hence, the electron geometry (eg) and molecular geometry (mg) of $CH_3^+$ is, trigonal planar and trigonal planar respectively.

7 0

2 years ago

For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox

ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: $m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent: $m_{N2}=4.274 g$

Explanation:

The reaction

$2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)$

Moles of nitrogen monoxide

Molecular weight: $M_{NO}=30 g/mol$

$n_{NO}=\frac{m_{NO}}{M_{NO}}$

$n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol$

Moles of hydrogen

Molecular weight: $M_{H2}=2 g/mol$

$n_{H2}=\frac{m_{H2}}{M_{H2}}$

$n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol$

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) Maximun ammount of nitrogen gas => when all NO reacted

$m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}$

$m_{N2}=10.682 g N_2$

2) Limiting reagent: $NO$

3) Ammount of excess reagent:

$m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}$

$m_{N2}=4.274 g$

8 0

3 years ago