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Alex777 [14]
3 years ago
14

Find the inverse of the given function. f(x) = -1/2√x + 3, x ≥ -3

Mathematics
2 answers:
shepuryov [24]3 years ago
5 0

Answer:

The inverse of the function is f^{-1}(x)=4x^2-3, for x\leq 0

Step-by-step explanation:

Given : Function f(x)=-\frac{1}{2}\sqrt{x+3}

To find : The inverse of the given function?

Solution :  

To find the inverse of the function we replace the value of x and y and then find y in terms of x which is the inverse of the function.

Let f(x)=y

y=-\frac{1}{2}\sqrt{x+3}                

Replace the value of x and y.

x=-\frac{1}{2}\sqrt{y+3}                  

Now, we solve in terms of x the value of y

-2x=\sqrt{y+3}  

(x must be negative)

Squaring both side,

(-2x)^2=(\sqrt{y+3})^2  

4x^2=y+3  

4x^2-3=y  

So, The inverse of the function is f^{-1}(x)=4x^2-3, for x\leq 0

inna [77]3 years ago
4 0
<span>Find the inverse of the given function.

f(x) = -1/2√x + 3, x ≥ -3

I will have to assume that you meant f(x) = -(1/2)sqrt(x) + 3.  If you actually meant f(x) = -(1/2)sqrt(x+3), then obviously the correct result would be different.

1.  Replace "f(x)" by "y:"  y </span>= -(1/2)sqrt(x) + 3
 2.  Interchange x and y:  x = -(1/2)sqrt(y) + 3
3.  Solve for y:  x-3=-(1/2)sqrt(y), so that 2(3-x)= sqrt(y) and y=+sqrt(2[3-x])
4.  Replace "y" with 

           -1
        f      (x) = sqrt(2[3-x])

Here, there are restrictions on x, since the domain of the sqrt function does not include - numbers.  The domain here is (-infinity,3]
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6 0
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The weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 l
joja [24]

1. Know what you're looking for:

The range is the difference between the lowest and highest values.

Your weight is 145.2 and can vary from the actual weight by maximum 0.3 lbs less or maximum 0.3 lbs more.


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3. Calculate the range of actual weights of the object :


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--> The answer is: <u>The range of actual weights of the object is 0.6 lbs.</u>


There you go! I really hope this helped, if there's anything just let me know! :)

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Step-by-step explanation:

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