Answer:
it would take rod B twice as much time
Explanation:
it would take rod B twice as much time as it is twice as thick and twice as long. Due to this reason it would take the electric charge not only more time but even more voltage to travel through the rod
30000 btuh /3413 btuh/kw. = 8.8 kw
8.8 kw/.746 kw/hp = 11.8 hp if COP is 1
11.8/3 hp (COP coefficient of performance) = 3.99 COP
>>>So yes a 3.0 hp compressor with a nominal COP of 4 will handle the 30,000 btuh load.
3.2 to 4.5 is expected COP range for an air cooled heat pump or a/c unit.
To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,

Here,
= Frequency of Source
= Speed of sound
f = Frequency heard before slowing down
f' = Frequency heard after slowing down
v = Speed of the train before slowing down
So if the speed of the train after slowing down will be v/2, we can do a system equation of 2x2 at the two moments, then,
The first equation is,



Now the second expression will be,



Dividing the two expression we have,

Solving for v, we have,

Therefore the speed of the train before and after slowing down is 22.12m/s
Answer:
Every 2.2 kg is 1 pound. So mulitply 19 * 2.2. It's gonna be equal to 41.8
Explanation:
Answer:
To write a number in scientific notation. First write a decimal point in the numbers so that there's only one digit to the left of the decimal point.