A ball of mass 0.500 kg is carefully balanced on a shelf that is 2.70 m above the ground. What is its gravitational potential en
1 answer:
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Answer: F = 2N
Explanation: If a current i is flowing in a wire of length L lying in a region of magnetic field B, then the magnetic force acting on the wire is given by
F = BIL
Please find the attached file for the solution
Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :
v = 2 m/s
Hence, their speed after collision is 2 m/s.
Answer:
1 bright fringe every 33 cm.
Explanation:
The formula to calculate the position of the m-th order brigh line (constructive interference) produced by diffraction of light through a diffraction grating is:
where
m is the order of the maximum
is the wavelength of the light
D is the distance of the screen
d is the separation between two adjacent slit
Here we have:
is the wavelength of the light
D = 1 m is the distance of the screen (not given in the problem, so we assume it to be 1 meter)
is the number of lines per mm, so the spacing between two lines is
Therefore, substituting m = 1, we find:
So, on the distant screen, there is 1 bright fringe every 33 cm.