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leva [86]
3 years ago
8

What impulse is needed to slow a 45kg object from 15m/s to 12m/s please show who to work problem

Physics
1 answer:
Rudik [331]3 years ago
8 0
'Impulse' is a change in momentum.
Momentum = (mass) x (velocity)

Final momentum = (45 x12) = 540 kilogram-meters/second
Original momentum = (45 x 15) = 675 kg-m/sec
Change in momentum = -135 kg-m/sec

The impulse required is 135 kg-m/sec in the direction
opposite to the way the object is moving.
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If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?
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Complete Question

In an action movie, the villain is rescued from the ocean by grabbing onto the ladder hanging from a helicopter. He is so intent on gripping the ladder that he lets go of his briefcase of counterfeit money when he is 130 m above the water. If the briefcase hits the water 6.0 s later, what was the speed at which the helicopter was ascending?

Answer:

The speed of the helicopter is u  =  7.73 \  m/s

Explanation:

From the question we are told that

   The height at which he let go of the brief case is  h =  130 m  

    The  time taken before the the brief case hits the water is  t =  6 s

Generally the initial speed of the  briefcase (Which also the speed of the helicopter )before the man let go of it is  mathematically evaluated using kinematic equation as

      s = h+  u t +  0.5 gt^2

Here s  is the distance covered by the bag at sea level which is zero

      0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>    0 = 130+  u * (6) +  0.5  *  (-9.8) * (6)^2

=>   u  =  \frac{-130 +  (0.5 * 9.8 *  6^2) }{6}

=>   u  =  7.73 \  m/s

     

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