Answer:
481 m
Explanation:
To fall 235 m, the time required is
t = √(2H/g)
t= √(2
235/9.8)
t=6.92 seconds.
The supplies will travel forward
6.92 69.4 ≈ 481 m
Therefore, the goods must be dropped 481 m in advance of the recipients.
Assuming there is no force of friction...
F = ma
F = (1300kg)(1.5m/s^2)
F = 1950N
Just multiply mass by acceleration.
1300 x 1.5 = 1950N.
Answer:
The velocity of the man from the frame of reference of a stationary observer is, V₂ = 5 m/s
Explanation:
Given,
Your velocity, V₁ = 2 m/
The velocity of the person, V₂ =?
The velocity of the person relative to you, V₂₁ = 3 m/s
According to the relative velocity of two
V₂₁ = V₂ -V₁
∴ V₂ = V₂₁ + V₁
On substitution
V₂ = 3 + 2
= 5 m/s
Hence, the velocity of the man from the frame of reference of a stationary observe is, V₂ = 5 m/s
For radio broadcasting, in electricity meters, in any generator.
