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Sunny_sXe [5.5K]
3 years ago
6

For water to change from a liquid to solid, thermal energy needs to be .

Chemistry
1 answer:
telo118 [61]3 years ago
6 0

answer: dispersed from the liquid so cold air can take its place

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What type of heat transfer happens when warm air in
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The answer is 1. Radiation
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True or false: Acids are more dangerous than bases. Explain.
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False because materials such as bleach, ammonia, or antifreeze, which are very strong bases, are extremely toxic to the human body

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3 years ago
an aqeous solution of oxalic acid h2c2o4 was prepared by dissolving a 0.5842g of solute in enough water to make a 100 ml solutio
vampirchik [111]

The question is incomplete, here is the complete question:

An aqeous solution of oxalic acid was prepared by dissolving a 0.5842 g of solute in enough water to make a 100 ml solution a 10 ml aliquot of this solution was then transferred to a volumetric flask and diluted to a final volume of 250 ml. How many grams of oxalic acid are in 100. mL of the final solution?

<u>Answer:</u> The mass of oxalic acid in final solution is 0.0234 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}     ......(1)

Given mass of oxalic acid = 0.5842 g

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

\text{Molarity of oxalic acid solution}=\frac{0.5842\times 1000}{90\times 100}\\\\\text{Molarity of oxalic acid solution}=0.0649M

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated oxalic acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted oxalic acid solution

We are given:

M_1=0.0649M\\V_1=10mL\\M_2=?M\\V_2=250.0mL

Putting values in above equation, we get:

0.0649\times 10=M_2\times 250.0\\\\M_2=\frac{0.0649\times 10}{250}=0.0026M

Now, calculating the mass of glucose by using equation 1, we get:

Molarity of oxalic acid solution = 0.0026 M

Molar mass of oxalic acid = 90 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

0.0026=\frac{\text{Mass of oxalic acid solution}\times 1000}{90\times 100}\\\\\text{Mass of oxalic acid solution}=\frac{0.0026\times 90\times 100}{1000}=0.0234g

Hence, the mass of oxalic acid in final solution is 0.0234 grams

6 0
4 years ago
The pH of a 0.05 M solution of acetic acid is 3. What is the value of the equilibrium constant for the dissociation of acetic ac
Leokris [45]

Answer:

k = 2,04x10⁻⁵

Explanation:

The equilibrium of acetic acid (CH₃COOH) in water is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺.

And the equilibrium constant is defined as:

k = [CH₃COO⁻] [H⁺] / [CH₃COOH] <em>(1)</em>

The equiibrium concentration of each specie if the solution of acetic acid is 0,05M is:

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[CH₃COO⁻] = x

[H⁺] = x

<em>-Where x is the degree of reaction progress-</em>

As the pH is 3, [H⁺] = 1x10⁻³M. That means x =  1x10⁻³M

Replacing in (1):

k = (1x10⁻³)² / 0,05 - 1x10⁻³

k = 1x10⁻⁶ / 0,049

<em>k = 2,04x10⁻⁵</em>

<em></em>

I hope it helps!

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