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madam [21]
3 years ago
10

How many grams of dipotassium succinate trihydrate (K2C4H4O4·3H2O, MW = 248.32 g/mol) must be added to 530.0 mL of a 0.0398 M su

ccinic acid solution to produce a pH of 5.908? Succinic acid has pKa values of 4.207 (pKa1) and 5.636 (pKa2).
Chemistry
1 answer:
marissa [1.9K]3 years ago
7 0
Let us write succinic acids as H2Suc
The first ionization is
H2Suc ----> HSuc- +  H+
The seond ionization is
HSuc- ---->  Suc-2 + H+
Calculate the H+ concentration of from the first ionization using pKa1.
Then, calculate the H+ concentration from the second ionization using pKa2.
Next, use the buffer equation to calculate the concentration of the salt in the solution. Then, use the given volume to get the number of moles of the salt. Finally, use the given molecular weight to get the mass.
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8 0
2 years ago
A glucose solution that is prepared for a patient should have a concentration of 180 g/L. A nurse has 18 g of glucose. How many
Anuta_ua [19.1K]
You start by using proportions to find the number of liters of solution:

180 g of glucose / 1 liter of solution = 18 g of glucose / x liter of solution


=> x = 18 g of glucose * 1 liter of solution / 180 g of glucose = 0.1 liter of solution.


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Answer: 0.1 liter of water.

 
6 0
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Answer:

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Explanation:

The name of the compound that gives hydrogen ion and chloride ions in the solution state is Hydrochloric acid.

Hydrochloric acid is made up of one atom of hydrogen and 1 atom of chlorine. We can also say, it is made up of 1 mole of hydrogen and 1 mole of chlorine.

 The formula of this compound is HCl;

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               HCl_{aq}    →   H⁺    +    Cl⁻  

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And I found it on Quora.com
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