This is generally true, though if either the acid or base (or both) is a weak base, the reaction may not go to completion and the properties of the mixture may be more complicated.
Answer:
A.) Brønsted-Lowry bases
Explanation:
Amines have a lone pair of electrons.
Brønsted-Lowry bases donate a lone pair of electrons in exchange for a hydrogen ion.
Therefore, if exposed to an acid, amines will give up electrons in order to bond with a hydrogen. This makes them Brønsted-Lowry bases.
Answer:
a) [H3O+] = 1.00 E-10 M ⇒ [OH-] = 1.0 E-4 M
b) [H3O+] = 1.00 E-4 M ⇒ [OH-] = 1.0 E-10 M
c) [H3O+] = 9.90 E-6 M ⇒ [OH-] = 1.0 E-9 M
Explanation:
- 14 = pH + pOH
- pH = - Log [H3O+]
a) [H3O+] = 1.00 E-10 M
⇒ pH = - Log(1.00 E-10) = 10
⇒ pOH = 14 - 10 = 4
⇒ 4 = - Log[OH-]
⇒ [OH-] = 1.0 E-4 M
b) [H3O+] = 1.00 E-4 M
⇒ pH = 4
⇒ pOH = 10
⇒ [OH-] = 1.0 E-10 M
c) [H3O+] = 9.90 E-6 M
⇒ pH = 5
⇒ pOH = 9
⇒ [OH-] = 1.0 E-9 M
Answer:
A. ionizing energy increases
Answer:
0.000237mL
Explanation:
0.237 x 10^-6L = 0.000000237L = mL
0.000237mL
