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madam [21]
3 years ago
10

How many grams of dipotassium succinate trihydrate (K2C4H4O4·3H2O, MW = 248.32 g/mol) must be added to 530.0 mL of a 0.0398 M su

ccinic acid solution to produce a pH of 5.908? Succinic acid has pKa values of 4.207 (pKa1) and 5.636 (pKa2).
Chemistry
1 answer:
marissa [1.9K]3 years ago
7 0
Let us write succinic acids as H2Suc
The first ionization is
H2Suc ----> HSuc- +  H+
The seond ionization is
HSuc- ---->  Suc-2 + H+
Calculate the H+ concentration of from the first ionization using pKa1.
Then, calculate the H+ concentration from the second ionization using pKa2.
Next, use the buffer equation to calculate the concentration of the salt in the solution. Then, use the given volume to get the number of moles of the salt. Finally, use the given molecular weight to get the mass.
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2 years ago
16.0 grams of molecular oxygen gas is equal to
IceJOKER [234]

One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.

As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.

To get the number of molecules present in 16 grams of O2, we will use the formula:

         No. of molecules = no. of moles x Avogadro's number (NA)-----  eq 1)

As we know:

                        The number of moles = mass/ molar mass of molecule

Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.

Putting the values in above formula:

                                                    = 16/32  

                                                     = 0.5 moles

Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1

                                No. of molecules = 0.5  x 6.02 * 10^23

                                   =3.01 x 10^23 molecules

or                 301,000,000,000,000,000,000,000 molecules

This means that 16 grams of 3.01 x 10^23 molecules of oxygen.

Hope it helps!

4 0
3 years ago
Read 2 more answers
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