A globe sitting on the desk can't demonstrate the speed of axial rotation
or the speed of orbital revolution.
Answer:
neutron.
Explanation:
subatomic particles include,
neutron.
proton.
electron.
hope it helps. :)
Answer:
The force needed is the weight of the rock minus the buoyant force.
Explanation:
The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

Where,
Depth of glass
Refraction index of water
Refraction index of glass
Refraction index of air
Depth of water
I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to



Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm
Kg . Meter per second (Kg.m/s)