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viva [34]
3 years ago
5

After a marathon many runners are given a shiny, aluminium blanket to wrap around their bodies. Explain why the blanket is shiny

and a metal?
Physics
1 answer:
vodomira [7]3 years ago
3 0
So then they get warmed up and can be seen easily

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Two planets have masses 2 x 10^23 kg and 5 x 10^22 kg, and the distance between them is 3 x 10^16 m. Calculate the gravitational
xxTIMURxx [149]

Explanation:

given,

mass of one planet (m1)=2*10^23 kg

mass of another planet (m2)=5*10^22kg

distance between them(d)=3*10^16m

gravitational constant(G)=6.67*10^-11Nm^2kg^-2

gravitational force between them(F)=?

we know,

F=Gm1m2/d^2

or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2

or, F=6.67*2*5*10^-11+23+22/3*3*10^32

or, F=66.7*10^34/9*10^32

or, F=7.41*10^34-32

•°• F=7.41*10^2

thus, the gravitational force between them is 7.14*10^2

3 0
3 years ago
External respiration takes place in the .....?
lions [1.4K]
<span>External respiration takes place in the </span>Bronchi to the capillaries. AND the internal respiration takes place from the capillaries to the cell tissues.
8 0
3 years ago
________ are more likely to be found near rural communities due to the large requirement for space.
nirvana33 [79]

Explanation/Answer:

Wind turbines are more likely to be found near rural communities due to the large requirement for space.

5 0
3 years ago
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The half of the moon facing the sun is always lit, but the different phases happen
Marizza181 [45]

Answer:

the answer is the spinning of the moon lets us see different amounts of light

Explanation:

you wanna know why uh yes ok lets cut to the magic so when the moon.

3 0
3 years ago
An electrician finds that a 1 m length of a certain type of wire has a resistance of 0.24 Ω . What is the total resistance of th
zlopas [31]

The resistance of a given conductor depends on its electrical resistivity (\rho), its length(L) and its cross-sectional area (A), as follows:

R=\frac{\rho L}{A}

In this case, we have L'=138L, \rho'=\rho and A'=A. So, the total resistance of the wire with length of 138m is:

R'=\frac{\rho' L'}{A'}\\R'=\frac{\rho 138L}{A}\\R'=138\frac{\rho L}{A}\\R'=138R\\R'=138(0.24\Omega)\\R'=33.12\Omega

5 0
3 years ago
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