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Ymorist [56]
3 years ago
14

Please Help! When does the double-slit interference have its first dark spot on either side of the central peak intensity?

Physics
2 answers:
Anvisha [2.4K]3 years ago
6 0
A, C, and D are true when a light spot appears, so those are false.

The answer is therefore B.
OlgaM077 [116]3 years ago
4 0

Explanation :

In double slit experiment, the consecutive dark and bright fringes are formed in the screen.

The condition for bright fringes is :

dsin\theta=n\lambda

and

The condition for dark fringe is :

dsin\theta=(n+\dfrac{1}{2})\lambda

So, the first dark spot on either side of the central peak intensity is observed when the when the paths d₁ and d₂ differ by half a wavelength.  

Hence, the correct option is (B).

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I NEED THIS DONE ASAP I WILL MARK YOU THE BRAINLIEST BUT NO LINKS
Cloud [144]

Answer:

1. Static Friction

2. Sliding friction

3. Fluid friction

4. is rolling friction

Sorry if i am wrong

Explanation:

4 0
3 years ago
In the following situations, which ball has the greatest kinetic energy?
mixer [17]
B. A Golf ball, because although just about the same size, the mass of a golf ball is greater than a ping pong ball.
7 0
3 years ago
Consider a river flowing toward a lake at an average velocity of 3 m/s at a rate of 500 m3/s at a location 90 m above the lake s
WINSTONCH [101]

Answer: a) 5 x 10^5 kg/s b) 444 MW

Explanation:

Kinetic energy per unit mass Ke is

Ke = V^2 / 2

Ke = 3^2 / 2 = 4.5 J/kg = 0.0045 kJ/kg

Now potential energy per unit mass Pe is

Pe = g x z = 9.8 x 90 = 882.9 J/kg = 0.8829 kJ/kg

The total mechanical energy of the River per unit mass e = Ke + Pe = 0.0045 + 0.8829 = 0.88744 J/kg

M = P x V = 1000 x 500 = 5 x 10^5 kg/s

b) power generation potential of the entire river at the location Wmax = Emech = M x Emech = 500,000 x 0.88744 = 444,000kW = 444MW

7 0
4 years ago
Calculate the height of a cliff if it takes 2. 35 s for a rock to hit the ground when it is thrown straight up from the cliff wi
scZoUnD [109]

The height of the cliff is 8.26 m.

Time taken by a rock to reach the ground from the cliff is t.

t = 2.35 seconds

The initial velocity at which rock is thrown straight up is u.

u = 8 m/s

The gravity of the earth is g.

g = 9.8 m/s²

The height of the cliff from where is rock is thrown straight up at the initial velocity of 8 m/s is,

Height= Initial \:  velocity × Time -  \frac{1}{2} Gravity \:  of  \: the  \: earth ×( Time) ^{2}

h = 8 \times 2.35 -  \frac{1}{2}  \times 9.8 \times (2.35) ^{2}

h = -8.26 m

Therefore, the height of the cliff is 8.26 m.

To know more about velocity, refer to the below link:

brainly.com/question/9552358

#SPJ4

7 0
1 year ago
A net force acts on a mass of 8.00 kg causing it to move from rest to a speed of 10.0 m/s in a time of 5.00 s. The bet force mus
wolverine [178]

Given data

mass (m) =8 Kg ,

speed (v) =10 m/s ,

time (t) = 5 s

determine magnitude of force (Fnet) = ?

                    we knoe that

                                        Fnet = m.a

                                                 = 8 × (v/t)       since a = v/t

                                                 = 8 × (10/5)

                                                 = 16 N

<em>Magnitude of net force is 16 N</em>


4 0
3 years ago
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