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madreJ [45]
4 years ago
11

He lowest energy bound state is characterized by:

Physics
1 answer:
Sergeu [11.5K]4 years ago
3 0

Answer:

h)a, c, and e

The lowest energy bound state characterized by

1. The lowest energy bound state  has zero nodes

2.The lowest energy bound state has nonzero probability to be found at x > a.

3.For large Vo, its energy is close to h2/8mL2 - Vo f) for large Vo, its energy is close to - Vo

Explanation:

As we know that when energy id high then states become unstable so the only lowest energy is stable and all other state is unstable.these unstable states try to reach on the lowest energy bound state.

The lowest energy bound state characterized by

1. The lowest energy bound state  has zero nodes

2.The lowest energy bound state has nonzero probability to be found at x > a.

3.For large Vo, its energy is close to h2/8mL2 - Vo f) for large Vo, its energy is close to - Vo

So the option h is correct.

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A marble is thrown horizontally with a speed of 7 m/s. When the marble lands, it hastraveled a horizontal displacement of 30 m.
Alex Ar [27]

Answer:

t = 4.28 s

Explanation:

The horizontal speed of a marble = 7 m/s

The horizontal displacement covered by the marble = 30 m

We need to find the time for which the marble is in air. Let the time is t. Using the formula for speed to find it as follows :

s=\dfrac{d}{t}\\\\t=\dfrac{d}{s}\\\\t=\dfrac{30\ m}{7\ m/s}\\\\=4.28\ s

So, it will in the air for 4.28 s.

6 0
3 years ago
Two identical small charged spheres are a certain distance apart, and each initially experiences an electrostatic force of magni
sweet-ann [11.9K]

Answer:

d) 1/4 F

Explanation:

The magnitude of electrostatic force between stationary charges is described by Coulomb's law. This law states that this force is proportional to the magnitudes of the charges:

F\propto q_1q_2

When each of the spheres has lost half its initial charge, we have:

q_1'=\frac{q_1}{2}\\q_2'=\frac{q_2}{2}

So, the new electrostatic force is:

F'\propto q_1'q_2'\\F'\propto \frac{q_1}{2}\frac{q_2}{2}\\F'\propto \frac{q_1q_2}{4}\\F'\propto\frac{1}{4}F

5 0
4 years ago
3. Write the numbers given below in scientific notation.
KIM [24]

Answer:
a) 3 * 10^9 ms
b) 1.6 * 10^-9 gm
c) 6.4 * 10^6 m
d) 5.48 * 10^5 s
Explanation:
Scientific notation is always written in [number from 0-10] (multiplied by) [10] raised to the power 'n'
4 0
2 years ago
A pilot heads his jet due east. The jet has a speed of 475 mi/h relative to the air. The wind is blowing due north with a speed
oksian1 [2.3K]

Explanation:

a. The velocity of the wind as a vector in component form will be represented as v vector:

    v=30j

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

    u=475i

c. The true velocity of the jet as a vector will be represented as w:

  w=u+v

  w=475i+30j

d.  The true speed of the jet will be calculated as:

    IwI=\sqrt{(475)^2+(30)^2}

    IwI=\sqrt{225625+900}

    IwI=\sqrt{226525}

    IwI=476 mi/h

e. The direction of the jet will be:

tita=tan^{-1}\frac{30}{475}

tita=tan^{-1}(0.0632)

tita=3.62degrees,or,N86.38degreesS

7 0
3 years ago
A women who normally weighs 400 N stands on top of a ladder so high she is one full additional earth radius above the surface of
AveGali [126]

The woman weighs 100N now.

Explanation:

Given:

F is given as 400N

one full additional earth radius formed

To Find:

Weight of the woman=?

Solution:

We know that gravitational force is inversely proportional to the square of radius.

f_g=\frac{1}{r^2}

where

f_g is the gravitational force

r^2 is the radius square

So when radius is doubled, the force becomes one fourth of the original.

Therefore \frac{1}{4} \times400 = 100N

3 0
3 years ago
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