A compound consisting of B, N, and H undergoes elemental analysis. The % composition by mass is found to be 40.28% B, 52.20% N,
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Answer:
The answer to your question is
4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O
Explanation:
Write the equation
C₇H₁₇ + O₂ ⇒ CO₂ + H₂O
Process
1.- Check if the equation is balanced
Reactants Element Products
7 C 1
17 H 2
2 O 3
As the number of reactants and products is different, we conclude that the reaction is unbalanced.
2.- Write a coefficient "7" to CO₂ and a coefficient of 17/2 to H₂O
C₇H₁₇ + O₂ ⇒ 7CO₂ + H₂O
Reactants Element Products
7 C 7
17 H 17
2 O 51/2
3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.
4C₇H₁₇ + 45 O₂ ⇒ 28 CO₂ + 34H₂O
Reactants Element Products
28 C 28
68 H 68
90 O 90
Explanation:
Formula to calculate hybridization is as follows.
Hybridization =
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
So, hybridization of is as follows.
Hybridization =
=
= 2
Hybridization of is sp. Therefore,
is a linear molecule. There will be only two electron groups through which Be is attached.
Similarly, hybridization of is calculated as follows.
Hybridization =
=
= 5
Therefore, hybridization of is
is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.
Thus, we can conclude that out of the given options is the correct examples of linear molecules for five electron groups.