Which frequency would be the third harmonic in a series for an open-pipe resonator if the fundamental is 440 Hz
1 answer:
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The age of a man whose normal blood pressure measures 123 mm of hg
9 years
<h3>What is Quadratic equation ?</h3>A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = a + bx + c, where a, b, and c are numbers and a cannot be 0
P(A) = 0.006 - 0.02a + 120
123 = 0.006- 0.02a + 120
0=0.006 - 0.02a - 3
you can use the quadratic equation formula to solve for the man's age.
A = (-b ± () ) / (2a)
A = (0.02 ± / (2*0.006)
A = (0.02 ± ) / 0.012
A = 9 , -5.67
Age of the man will be 9 years
To learn more about quadratic equation here
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Using the cosine rule (a^2 = b^2 + c^2 - 2bc cos A), we can work out the displacement:
Displacement = a
b = 30
c = 50
A = 180 - 35 = 145 degrees.
a^2= 900 + 2500 -1500*-0.81915...
= 3400 + 1228.728...
= 4628.72...
a = 68.034...
= 68.0m (to 3s.f.).
To work out the angle from starting place, use another configuration of the cosine rule:
:
cos (C)=
= 3028.7.../4080
= 0.7423...
C = 42.069... degrees
= 042 bearing
Displacement = a
b = 30
c = 50
A = 180 - 35 = 145 degrees.
a^2= 900 + 2500 -1500*-0.81915...
= 3400 + 1228.728...
= 4628.72...
a = 68.034...
= 68.0m (to 3s.f.).
To work out the angle from starting place, use another configuration of the cosine rule:
cos (C)=
= 3028.7.../4080
= 0.7423...
C = 42.069... degrees
= 042 bearing
Answer:
Explanation:
Let the force at the support end is R and at the left end is F.
According to the equilibrium condition
F + R = 280 + 500
F + R = 780 .... (1)
Take moments about G.
F x 1.5 + R x 0.5 = 500 x 1.5
3F + R = 1500 .... (2)
Subtract equation (1) from equation (2), we get
2F = 1500 - 780
F = 360 N
R = 780 - 360
R = 420 N
(a) Force at support is 420 N
(b) force at the left end is 360 N.
