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Lana71 [14]
2 years ago
5

Which frequency would be the third harmonic in a series for an open-pipe resonator if the fundamental is 440 Hz

Physics
1 answer:
Yanka [14]2 years ago
8 0

Answer:

1320 Hz

Explanation:

The third harmonic is given as 3fo, where fo is the fundamental frequency.

The fundamental frequency is the lowest frequency that can occur in a pipe. In an open pipe, both even and odd harmonics occur which are multiples of the fundamental frequency fo. Hence the harmonics in an open pipe are; 2fo, 3fo,4fo..... etc.

For the third harmonic; 3fo = 3 (440 Hz) = 1320 Hz

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Answer:

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Explanation:

From the question we are told that

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Given that the spaceship is rotating it implies that the force experienced by the occupant is a centripetal force so

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=>    v^2  =   [\frac{2\pi}{T}] ^2

=>     \frac{\frac{4\pi^2 r^2}{T^2} }{r}  = 0.5g

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=>         T  = \sqrt{ \frac{4\pi^2 r}{0.5g}}

substituting values

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