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taurus [48]
3 years ago
7

A chemistry student mixes 5 grams of sodium chloride (NaCl) in 100 ml of water and stirs until all of the salt is dissolved. Onc

e dissolved, the student measures the electrical conductivity of the solution. An additional 5 grams of NaCl is then dissolved in the solution. Which statement MOST accurately describes how the additional five grams of salt will affect the electrical conductivity of the solution? A) The conductivity of the solution will increase because more ions are being added to the solution. B) The conductivity of the solution will decrease because salt is an insulator and more is being added. C) The conductivity of the solution will decrease because the concentration has changed--the solution is more dense. D) The conductivity of the solution will increase because additional electrical potential is being added to the solution.
Physics
1 answer:
vichka [17]3 years ago
4 0
The answer would be a
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Particle accelerators, such as the Large Hadron Collider, use magnetic fields to steer charged particles around a ring Consider
coldgirl [10]

Answer:

\beta= 3.49x10^{-8}T

Explanation:

The magnetic field can be find using the equation

m*v^2/r=q*v*\beta

You can cancel a element of v'

m*v/r=q*\beta

C=36*1m=2\pi*r

r=\frac{36}{2\pi } =5.7295m

Solve to magnetic field

\beta=\frac{m*v^2}{r*q}

The charge and mass of the proton are:

m_p=1.6x10^{27}kg, q_p=1.6x10^{-19}C

Replacing numeric

\beta=\frac{1.6x10^{-27}kg*2x10m/s}{1.6x10^{-19}C*5.73m}

\beta= 3.49x10^{-8}T

6 0
3 years ago
11. Two point charges, initially 1 cm apart, are moved to a distance of 3 cm apart. By what factor
vampirchik [111]

Answer:

9

Explanation:

8 0
3 years ago
If you know all of the forces acting on a moving object, can you tell in which direction the object is moving? if the answer is
Montano1993 [528]

No, knowing all the forces is not enough to know the direction of motion.

<h3>How to use Newton's laws?</h3>

The second Newton's law states that:

F = m*a

This says <u><em>"force equals mass times acceleration".</em></u>

Where acceleration is the rate of change of the speed. From that equation, we conclude that the acceleration is in the same direction that the net force.

So, if we know all the forces acting on an object, we know the net force acting on it, then we know the direction of the acceleration.

<h3>Is this enough to know the direction in which it is moving?</h3>

No, the object does not need to move in the same direction than its acceleration, the direction of motion will also depend on the initial velocity of the object (if it is initially moving with constant speed).

If we don't know that, we can't find the direction of motion.

An example of this can be a car going at 100km/h east-wise.

Then we apply a net force due west, then we have an acceleration due west. But as the initial direction of motion was east, the car will still move to the east, but the velocity will decrease gradually.

So as you can see in that example, we need to know the initial velocity to know the direction in which the object is moving.

If you want to know more about acceleration, you can read:

brainly.com/question/605631

8 0
3 years ago
A large rock of mass me materializes stationary at the orbit of Mercury and falls into the sun. Itf the Sun has a mass ms and ra
son4ous [18]

Answer:

The answer is v = \sqrt{2G\frac{M_s}{R^2}(R-r_s)}.

Explanation:

From the law of gravity,

F = G \frac{Mm}{r^2}

considering F as a conservative force, F = - \nabla U,

the general expression for gravitational potential energy is

U = -G \frac{Mm}{r},

where G is the gravitational constant, M and m are the mass of the attracting bodies, and r is the distance between their centers. The negative sign is because the force approaches zero for large distances, and we choose the zero of gravitational potential energy at an infinite distance away.

However, as the mass of the Sun is much greater than the mass of the rock, the gravitational acceleration is defined as

g = -G \frac{M}{r^2},

(the negative sign indicates that the force is an attractive force), and the potential energy between the rock and the Sun is

U = g M_e R,

which is actually the total energy of the system, because the rock materializes stationary at this point (there is no radial kinetic energy).

When the rock hits the surface of the Sun, almost all potential energy is converted to kinetic energy, but not all because the Sun is not a puntual mass. So the potential energy converted to kinetic energy is

U_p = g M_e(R- r_s),

then, the kinetik energy when the rock hits the surface is

U_k =\frac{1}{2}M_e v^2 = g M_e(R- r_s),

so

v = \sqrt{2g(R-r_s)}

where g is the gravitational acceleration generated by the Sun at R,

g = G \frac{M_s}{R^2}.

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3 years ago
Two boys wearing roller skates are standing on a smooth surface with the palms of their hands touching and their arms bent, as s
vlada-n [284]

Boy X and Boy Y both move backward in opposite directions.
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