Answer:
b
Explanation:
friction needs two objects
the two objects need to touch each other
the two objects need to either have relative movement or, tend to have relative movement urge. (kinetic friction or static friction)
Answer: +2.10V
Explanation:

Using Nernst equation :

![E_{cell}=E^o_{cell}-\frac{0.059}{n}\log [Al^{3+}]^2\times [I^-]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B0.059%7D%7Bn%7D%5Clog%20%5BAl%5E%7B3%2B%7D%5D%5E2%5Ctimes%20%5BI%5E-%5D%5E6)
where,
= standard emf for the cell = +2.20 V
n = number of electrons in oxidation-reduction reaction = 6
= emf of the cell = ?
= concentration = 
= concentration = 
Now put all the given values in the above equation, we get:
![E_{cell}=+2.20-\frac{0.059}{6}\log [5.0\times 10^{-3}]^2\times [0.10]^6](https://tex.z-dn.net/?f=E_%7Bcell%7D%3D%2B2.20-%5Cfrac%7B0.059%7D%7B6%7D%5Clog%20%5B5.0%5Ctimes%2010%5E%7B-3%7D%5D%5E2%5Ctimes%20%5B0.10%5D%5E6)

The standard emf for the cell using the overall cell reaction below is +2.10 V