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3 years ago

For refraction to occur in a wave, the wave must

Physics

2 answers:

UNO [17]3 years ago

6 0

Enter a new medium at an angle.

fgiga [73]3 years ago

3 0

The answer is:

C - enter a new medium at an angle

Hope this helps :)

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The difference between relational and reactive aggression is that relational aggression is ______, whereas reactive aggression i

givi [52]

Answer:

Social, physical behavior

Explanation:

The relational aggression is the aggression which caused or give to person by doing harm to his or her relationship or social image.

Reactive aggression is the aggression which is caused by threatening someone, or caused by provocation, or caused due to frustration.

Therefore, the basic differentiation in between both the aggression is that relational aggression is caused by by damaging social status whereas reactive aggression is caused through physical behavior.

8 0

2 years ago

A solar cell generates a potential difference of 0.25 V when a 550 Ω resistor is connected across it, and a potential difference

Andre45 [30]

a) $400 \Omega$

b) 0.43 V

c) 0.44 %

Explanation:

For a battery with internal resistance, the relationship between emf of the battery and the terminal voltage (the voltage provided) is

$V=E-Ir$ (1)

where

V is the terminal voltage

E is the emf of the battery

I is the current

r is the internal resistance

In this problem, we have two situations:

1) when $R_1=550 \Omega$ , $V_1=0.25 V$

Using Ohm's Law, the current is:

$I_1=\frac{V_1}{R_1}=\frac{0.25}{550}=4.5\cdot 10^{-4} A$

2) when $R_2=1000 \Omega$ , $V_2=0.31 V$

Using Ohm's Law, the current is:

$I_2=\frac{V_2}{R_2}=\frac{0.31}{1000}=3.1\cdot 10^{-4} A$

Now we can rewrite eq.(1) in two forms:

$V_1 = E-I_1 r$

$V_2=E-I_2 r$

And we can solve this system of equations to find r, the internal resistance. We do it by substracting eq.(2) from eq(1), we find:

$V_1-V_2=r(I_2-I_1)\\r=\frac{V_1-V_2}{I_2-I_1}=\frac{0.25-0.31}{3.1\cdot 10^{-4}-4.5\cdot 10^{-4}}=400 \Omega$

To find the electromotive force (emf) of the solar cell, we simply use the equation used in part a)

$V=E-Ir$

where

V is the terminal voltage

E is the emf of the battery

I is the current

r is the internal resistance

Using the first set of data,

$V=0.25 V$ is the voltage

$I=4.5\cdot 10^{-4}A$ is the current

$r=400\Omega$ is the internal resistance

Solving for E,

$E=V+Ir=0.25+(4.5\cdot 10^{-4})(400)=0.43 V$

In this part, we are told that the area of the cell is

$A=4.0 cm^2$

While the intensity of incoming radiation (the energy received per unit area) is

$Int.=5.5 mW/cm^2$

This means that the power of the incoming radiation is:

$P=Int.\cdot A=(5.5)(4.0)=22 mW = 0.022 W$

This is the power in input to the resistor.

The power in output to the resistor can be found by using

$P'=I^2R$

where:

$R=1000 \Omega$ is the resistance of the resistor

$I=3.1\cdot 10^{-4} A$ is the current on the resistor (found in part A)

Susbtituting,

$P'=(3.1\cdot 10^{-4})^2(1000)=9.61\cdot 10^{-5} W$

Therefore, the efficiency of the cell in converting light energy to thermal energy is:

$\epsilon = \frac{P'}{P}\cdot 100 = \frac{9.6\cdot 10^{-5}}{0.022}=0.0044\cdot 100 = 0.44\%$

7 0

2 years ago

The fact that Voyager 10 continues to speed out of the solar system, even though its rockets have no fuel, is an example of Grou

miv72 [106K]

Answer:

The universal law of gravitation.

PE = m * G M / R^2 potential energy of mass m due to attractive forces

If the kinetic energy of mass m is greater than the energy due to the attractive masses then then mass m can continue indefinitely away from the attracting masses.

8 0

2 years ago

Economy?

Mrrafil [7]

Answer:

I. don't. get. this. question

C. Demand increases

Pace increases

5 0

2 years ago

The liquid contained in batteries that conducts electric charge is called the: solution, electrolyte, suspension, colloid

blondinia [14]

Answer:

The liquid contained in batteries that conducts electric charge is called the. electrolyte.

7 0

2 years ago