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777dan777 [17]
4 years ago
9

For refraction to occur in a wave, the wave must

Physics
2 answers:
UNO [17]4 years ago
6 0
Enter a new medium at an angle.
fgiga [73]4 years ago
3 0

The answer is:

C - enter a new medium at an angle

Hope this helps :)

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The acceleration of gravity at the surface of Moon is 1.6 m/s2 . A 5.0 kg stone thrown upward on Moon reaches a height of 20 m.
kramer

Answer:

(a) 8 m/s

(b) 5 s

Explanation:

(a)

Using,

V² = U²+2gh ......................... Equation 1

Where V = final velocity, U = Initial velocity, g = acceleration due to gravity on the surface of the moon, h = height reached.

Given: V = 0 m/s ( At it's maximum height), g = -1.6 m/s² ( as its moves against gravity), h = 20 m.

Substitute into equation 1

0 = U²+[2×20×(-1.6)]

-U² = - 64

U² = 64

U = √64

U = 8 m/s.

(b)

V = U +gt.................... Equation 2

Where t = time to reach the maximum height.

Given: V = 0 m/s ( At the maximum height), g = -1.6 m/s² ( Moving against gravity), U = 8 m/s.

Substitute into equation 2

0 = 8+(-1.6t)

-8 = -1.6t

-1.6t = -8

t = -8/-1.6

t = 5 s.

5 0
3 years ago
What is Particle-antiparticle annihilation after watching the video minutephysics Antimatter Explained
LenKa [72]

Answer:

Particle-antiparticle annihilation is the result of a direct interaction between a particle and its corresponding anti particle, like a proton and an anti-proton or an electron and a positron. The result of such interaction is the production of two powerful gamma rays, each of whom has an energy roughly equal to E = mc^2, where m is the mass of the particle.

3 0
3 years ago
Freeeeeeeee poinnttttsssss
RUDIKE [14]

Answer:

k

Explanation:

umm really

5 0
3 years ago
Determine the minimum angle at which a roadbedshould be banked
poizon [28]

To solve this problem, apply the concepts related to the relationship given between the centripetal Force and the Weight.

The horizontal force component is equivalent to the weight of the car, while the vertical component is linked to the centripetal force exerted on the car, therefore,

T cos\theta = mg \rightarrow T = \frac{mg}{cos\theta}

Tsin\theta = \frac{mv^2}{r} \rightarrow T = \frac{mv^2/r}{sin\theta}

Equating both equation we have that,

\frac{mv^2}{r} = mgtan\theta

tan\theta = \frac{v^2}{rg}

Rearranging to find the angle we have that,

\theta = tan^{-1} (\frac{v^2}{rg})

Our values are given as,

r = 2.00*10^2m

v = 20m/s

\theta = tan^{-1}(\frac{20^2}{(2*10^{2})(9.8)})

\theta = 11.53 \°

Therefore the minimum angle will be 11.53°

5 0
3 years ago
In a thundercloud there may be an electric charge of 24 C near the top of the cloud and −24 C near the bottom of the cloud. If t
lidiya [134]

Answer:

Electric force, F=1.29\times 10^6\ N

Explanation:

Given that,

Charge 1, q_1=24\ C

Charge 2, q_2=-24\ C

Distance between charges, d = 2 km

The electric force is given by :

F=k\dfrac{q_1q_2}{d^2}

k is the electrostatic constant

F=8.98755\times 10^9\times \dfrac{(24)^2}{(2\times 10^3)^2}

F = 1294207.2 N

or

F=1.29\times 10^6\ N

Hence, this is the required solution.

5 0
4 years ago
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