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zhenek [66]
4 years ago
12

Choose the appropriate word choices below that correctly complete the blanks in the following three sentences: At the beginning,

the object is at the origin and moving to the left. In the first half of its motion, the object moves to the left with ________ velocity. Then, the motion of the object changes. In the second half of its motion, the object________ due to a ________ acceleration that is ________ in magnitude.
Physics
1 answer:
Pepsi [2]4 years ago
5 0

Answer:

Constant

Accelerates

Constant

Positive

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What is the force on an electron in a CRT when it’s moving at 2.5 × 105 meters/second perpendicular to a magnetic field of 1.5 t
Firdavs [7]
F = Magnetic Force
B = Magnetic Field
V = Velocity

*The vectors from the photo you get doing the left-hand rule.

The magnetic force is always perpendicular to the magnetic field.

And as told in the statement, the electron is moving perpendicular to a magnetic field, that is, the Velocity forms an 90 degree angle / Right angle with the magnetic field.

The formula to find the Magnetic Force is:

f = |q| \times v \times b \times sin \: \theta

Where "q" is the Charge and the sin theta is the angle formed by the Velocity and Magnetic Field, in this case it's 90°. Sin 90° = 1.

f = |- 1.6 \times {10}^{ - 19} | \times 2.5 \times {10}^{5} \times 1.5 \times 1 \\ f = 6 \times {10}^{ - 19 + 5} \\ f = 6 \times {10}^{ - 14} \: newtons
Newton (N) = C x m/s x T = (C x m x T)/s

4 0
4 years ago
A crane lifts a concrete block, whose weight is 60,000N to a height of 20m in 30s.
Nataly_w [17]

Answer:

C

Explanation:

Power formula is power=work(joules)/time(seconds). the Work formula is force (newtons) times the distance from the starting point. Calculate work first: 60,000N x20m = 1,200,000 joules. Then plug into power formula: 1,200,000j/ 30 seconds= 40,000 W

7 0
3 years ago
PEg=mgh For a mass of 60kg and 10m high
Anuta_ua [19.1K]
Assuming that the gravitational field strength is 10 N/kg, the sum would look like this:
PEg=mgh
=60×10×10
=6000J
However, you will need to check that you are not meant to be using 9.8 N/kg as the gravitational field strength.
3 0
3 years ago
At what distance will a 45 W lightbulb have the same apparent brightness as a 130 W bulb viewed from a distance of 35 m ? (Assum
Sloan [31]

Answer:

20.6 m

Explanation:

P₁ = Power of first bulb = 45 W

P₂ = Power of second bulb = 130 W

r₁ = distance from the first bulb

r₂ = distance from the second bulb = 35 m

Using the equation

\frac{P_{1}}{r_{1}^{2}} = \frac{P_{2}}{r_{2}^{2}}

Inserting the values

\frac{45}{r_{1}^{2}} = \frac{130}{35^{2}}

r₁ = 20.6 m

5 0
4 years ago
A motorcyclist changes his speed from 20 km / h to 100 km / h in 3 seconds, maintaining a constant acceleration in that time int
nadya68 [22]

Answer:

2000 N

Explanation:

20 km/h = 5.56 m/s

100 km/h = 27.78 m/s

F = ma

F = m Δv/Δt

F = (200 kg + 80 kg) (27.78 m/s − 5.56 m/s) / (3 s)

F = 2074 N

Rounded to one significant figure, the force is 2000 N.

6 0
3 years ago
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