a 30-cm-tall, 6.0-cm-diameter cylindrical beaker is filled to its brim with water. part a what is the downward force of the wate
1 answer:
The force on the bottom of the beaker is 8.31 N.
<h3 /><h3>How can we calculate the force?</h3>To calculate the force on the bottom of the beaker we are using the formula,
F = PA
Here we are given,
A = area of the beaker.
To calculate the force we have to calculate the pressure P first.
To calculate the pressure P we are using the formula,
P= ρgh
ρ= density of water.
g= the acceleration due to gravity.
h=the height of the water.
Now we put the values in the formula, we get,
P= ρgh
Or, P= (1000)×(9.8)×(0.30)
Or, P= 2940 Pa.
From the above calculation we can say that the pressure P= 2940 Pa.
Now we put the values in the force formula,
F=PA
Or, F= 2940×
Or, F = 2940×π×(0.03)²
Or, F= 8.31N
From the above calculation we can conclude that, The force on the bottom of the beaker is 8.31 N.
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The dimensions of the rectangle are:
l = 50 m
b = m
The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides.
<h3>How do we find a perimeter of a rectangle?</h3>The perimeter of a rectangle,denoted by P is given by the formula, P=2l+2b, where l is the length and b is the breadth of the rectangle.
<h3>Given:</h3>As per the question:
Perimeter of the room is given as P = 200 m
The region is rectangular having a semicircle at each end.
Now,
Let 'l' be the length of the rectangle, 'b' be its breadth and 'r' be the radius of the semi-circle at each end.
Then, Area of the given rectangle, A = lb
Perimeter of the room, P is =
Therefore,
Now,
Area, A =
Now, differentiate A w.r.t l:
Again differentiating w.r.t 'l', we get:
< 0
Thus we get maximum are when
Therefore,
l = 50 m
Now, from
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