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lions [1.4K]
1 year ago
14

a 30-cm-tall, 6.0-cm-diameter cylindrical beaker is filled to its brim with water. part a what is the downward force of the wate

r on the bottom of the beaker?
Physics
1 answer:
bogdanovich [222]1 year ago
7 0

The force on the bottom of the beaker is 8.31 N.

<h3 /><h3>How can we calculate the force?</h3>

To calculate the force on the bottom of the beaker we are using the formula,

F = PA

Here we are given,

A = area of the beaker.

To calculate the force we have to calculate the pressure P first.

To calculate the pressure P we are using the formula,

P= ρgh

ρ=  density of water.

g= the acceleration due to gravity.

h=the height of the water.

Now we put the values in the formula, we get,

P= ρgh

Or, P= (1000)×(9.8)×(0.30)

Or, P= 2940 Pa.

From the above calculation we can say that the pressure P= 2940 Pa.

Now we put the values in the force formula,

F=PA

Or, F=  2940×\pi r^{2}

Or, F = 2940×π×(0.03)²

Or, F= 8.31N

From the above calculation we can conclude that, The force on the bottom of the beaker is 8.31 N.

Learn more about Force:

brainly.com/question/12970081

#SPJ4

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Calculate the average linear momentum of a particle described by the following wavefunctions: (a) eikx, (b) cos kx, (c) e−ax2 ,
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Answer:

a) p=0, b) p=0, c) p= ∞

Explanation:

In quantum mechanics the moment operator is given by

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We apply this equation to the given wave functions

a)  φ = e^{ikx}

        .d φ dx = i k e^{ikx}

We replace

        p = h’ k e^{ikx}

        i i = -1

The exponential is a sine and cosine function, so its measured value is zero, so the average moment is zero

            p = 0

b) φ = cos kx

           p = h’ k sen kx

The average sine function is zero,

          p = 0

c) φ = e^{-ax^{2} }

         d φ / dx = -a 2x  e^{-ax^{2} }

         .p = i a g ’2x  e^{-ax^{2} }

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Mary and her younger brother Alex decide to ride the carousel at the State Fair. Mary sits on one of the horses in the outer sec
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Mary and her younger brother Alex decide to ride the carousel at the State Fair, Mary's and Alex's  angular speed M and tangential speed vM is mathematically given as

Mary's and Alex's  angular speed=1.43

Tangential speed mary=3.22 m/s

Tangential speed alex =2.260m/s

<h3>What is Mary's and Alex's angular speed M and tangential speed vM?</h3>

Generally, the equation for angular speed is mathematically given as

w=2\pi /T\\\\Therefore\\\\w=2\pi/3.9

w = 1.61 rev/see 3.9

Centripetal acc mary = v^2/r

Centripetal acc mary  = w^2r

Centripetal acc mary = w^2x 2m

Centripetal acc. of Alex = w²x L.u

Therefore

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Hence

tang. speed V=Wr

tang. speed of mary = 1.61x2 = 3.22 m/s

tang. speed of Alex: 1.61X1·4 =2.260m/s

Read more about Speed

brainly.com/question/4931057

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