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lions [1.4K]
1 year ago
14

a 30-cm-tall, 6.0-cm-diameter cylindrical beaker is filled to its brim with water. part a what is the downward force of the wate

r on the bottom of the beaker?
Physics
1 answer:
bogdanovich [222]1 year ago
7 0

The force on the bottom of the beaker is 8.31 N.

<h3 /><h3>How can we calculate the force?</h3>

To calculate the force on the bottom of the beaker we are using the formula,

F = PA

Here we are given,

A = area of the beaker.

To calculate the force we have to calculate the pressure P first.

To calculate the pressure P we are using the formula,

P= ρgh

ρ=  density of water.

g= the acceleration due to gravity.

h=the height of the water.

Now we put the values in the formula, we get,

P= ρgh

Or, P= (1000)×(9.8)×(0.30)

Or, P= 2940 Pa.

From the above calculation we can say that the pressure P= 2940 Pa.

Now we put the values in the force formula,

F=PA

Or, F=  2940×\pi r^{2}

Or, F = 2940×π×(0.03)²

Or, F= 8.31N

From the above calculation we can conclude that, The force on the bottom of the beaker is 8.31 N.

Learn more about Force:

brainly.com/question/12970081

#SPJ4

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A motorcycle accelerated from 10 metre per second to 30 metre per second in 6 seconds. How far did it travel in this time ?
Ber [7]
U=10 m/s
v=30 m/s
t=6 sec

therefore, a=(v-u)/t
                   =(30-10)/6
                   =(10/3) ms^-2

now, displacement=ut+0.5*a*t^2
                              =60+ 0.5*(10/3)*36
                              =120 m
And you can solve it in another way:

v^2=u^2+2as
or, s=(v^2-u^2)/2a
       =(900-100)/6.6666666.......
       =120 m

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The force F required to compress a spring a distance x is given by F 2 F0 5 kx where k is the spring constant and F0 is the prel
IrinaVladis [17]

Answer:

a)W=8.333lbf.ft

b)W=0.0107 Btu.

Explanation:

<u>Complete question</u>

The force F required to compress a spring a distance x is given by F– F0 = kx where k is the spring constant and F0 is the preload. Determine the work required to compress a spring whose spring constant is k= 200 lbf/in a distance of one inch starting from its free length where F0 = 0 lbf. Express your answer in both lbf-ft and Btu.

Solution

Preload = F₀=0 lbf

Spring constant k= 200 lbf/in

Initial length of spring x₁=0

Final length of spring x₂= 1 in

At any point, the force during deflection of a spring is given by;

F= F₀× kx  where F₀ initial force, k is spring constant and x is the deflection from original point of the spring.

W=\int\limits^2_1 {} \, Fds \\\\\\W=\int\limits^2_1( {F_0+kx} \,) dx \\\\\\W=\int\limits^a_b {kx} \, dx ; F_0=0\\\\\\W=k\int\limits^2_1 {x} \, dx \\\\\\W=k*\frac{1}{2} (x_2^{2}-x_1^{2}  )\\\\\\W=200*\frac{1}{2} (1^2-0)\\\\\\W=100.lbf.in\\\\

Change to lbf.ft by dividing the value by 12 because 1ft=12 in

100/12 = 8.333 lbf.ft

work required to compress the spring, W=8.333lbf.ft

The work required to compress the spring in Btu will be;

1 Btu= 778 lbf.ft

?= 8.333 lbf.ft----------------cross multiply

(8.333*1)/ 778 =0.0107 Btu.

6 0
3 years ago
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