Answer:
We need 2.02 grams of NH3
Explanation:
Step 1: Data given
Mass of methanol = 475 grams
Molality of the solution = 0.250 M
Molar mass of NH3 =17.03 g/mol
Molar mass of = methanol = 32.04g/mol
Step 2: Calculate moles NH3
Molality = 0.250 m = mol NH3 / 0.475 kg
moles NH3 = 0.250 molal * 0.475 kg
Moles NH3 = 0.11875 moles
Step 3: Calculate the mass of NH3
Mass NH3 = moles NH3 * molar mass NH3
Mass NH3 = 0.11875 mol * 17.03 g/mol
Mass NH3 = 2.02 grams
We need 2.02 grams of NH3
Answer:25grams
Explanation: the mass stays the same even when it changes form
Complete question
The complete question is shown on the first uploaded image
Answer:
The value is
Explanation:
From the question we are told that
The equation is

Generally the equilibrium is mathematically represented as
Here
is the concentration of water vapor which is mathematically represented as
![[H_2O ] = \frac{n_w}{V_s }](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%20%5Cfrac%7Bn_w%7D%7BV_s%20%7D)
Here
is the volume of the solution given as 8.9 L
is the number of moles of water vapor which is mathematically represented as

Here
is the mass of water given as 2.00 g
and
is the molar mass of water with value 18 g/mol
So

=> 
So
![[H_2O ] = \frac{0.11}{8.9 }](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%20%5Cfrac%7B0.11%7D%7B8.9%20%7D)
=> ![[H_2O ] = 0.01236 \ M](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%200.01236%20%5C%20%20M%20)
Also
is the concentration of hydrogen gas which is mathematically represented as
![[H ] = \frac{n_v}{V_s }](https://tex.z-dn.net/?f=%5BH%20%5D%20%3D%20%20%5Cfrac%7Bn_v%7D%7BV_s%20%7D)
Here
is the volume of the solution given as 8.9 L
is the number of moles of hydrogen gas which is mathematically represented as

Here
is the mass of water given as 4.77 g
and
is the molar mass of water with value 2 g/mol
So

=> 
So
![[H_2O ] = \frac{2.385}{8.9 }](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%20%5Cfrac%7B2.385%7D%7B8.9%20%7D)
=> ![[H_2O ] = 0.265 \ M](https://tex.z-dn.net/?f=%5BH_2O%20%5D%20%3D%20%200.265%20%5C%20%20M%20)
So
=>
<em>The Molecular Mass for Phosphorus is 31 grames / mole.
So, 31g. P.....................1 mole
2.3g. P ..........................x mole
</em>

<em>
</em>