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3 years ago

Waves bounce back when they meet a surface. This phenomenon is called...

Physics

1 answer:

tamaranim1 [39]3 years ago

4 0

Answer:

A reflection

Explanation:

Reflection – when a wave hits a surface, any part of the wave that cannot pass through the surface bounces back. This interaction with a surface is called reflection.

Another way to explain it is

Reflection occurs when waves bounce back from a surface they cannot pass through.

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What si the name of the state change water is going through as it boils?

Blababa [14]

It evaporates into a vapor

~~~hope this helps~~~
~~have a beautiful day~~
~davatar~

3 0

3 years ago

suppose you use three different scales to weigh bag of oranges one scale says the bag weighs 2.1 lbs a second says it weighs 2.2

Ber [7]

Answer:

It would be 2.2 if you have to round the five to the one but if your not rounding the number, it'd be 2.1.

Explanation:

4 0

3 years ago

A newly discovered planet is found to have a density if 2/3pe and a radius of 2RE, where PE and RED are the density and radius o

Liono4ka [1.6K]

Missing question in the text of the exercise. Found on internet:
"What is the acceleration due to gravity on the surface of the planet?"

Solution:
The gravitational acceleration at Earth's surface is given by:
$g= \frac{GM}{r^2}$
where
G is the gravitational constant
M is the Earth's mass
r is the Earth's radius

The Earth's mass can be rewritten also as the product between the Earth's density, $d$ , and its volume (the volume of a sphere of radius r):
$M=dV=d ( \frac{4}{3} \pi r^3)= \frac{4}{3} \pi d r^3$

Now let's call M' the mass of the new planet, r' its radius and d' its density. The acceleration due to gravity on the surface of the new planet is
$g' = \frac{GM'}{r'^2}$ (1)
so we need to find M' and r'.

The problem says the radius of the new planet is twice the Earth's radius:
$r'=2r$ (2)
and that its density is 2/3 of Earth's density:
$d'= \frac{2}{3} d$
so the mass M' of the new planet is, with respect to the Earth's mass:
$M' = d'V' = \frac{4}{3} \pi d' (r')^3 = \frac{4}{3} \pi ( \frac{2}{3}d) (2r)^3 = ( \frac{4}{3} \pi d r^3 )( \frac{16}{3}) = \frac{16}{3} M$ (3)

And if we substitute (2) and (3) into (1), we find the gravitational acceleration on the surface of the new planet:
$g'= \frac{G( \frac{16}{3}M) }{(2r)^2}= \frac{GM}{r^2} \frac{4}{3} = \frac{4}{3}g$
And since $g=9.81 m/s^2$ , we find
$g'= \frac{4}{3}(9.81 m/s^2)=13.1 m/s^2$

8 0

3 years ago

__________ is the correct method of recording numerical information from an experiment.

choli [55]

Answer:

The quantitative method

Explanation:

<em>Quantitative method is the use of numbers, graphs, logic, tables, charts, stadistics, etc.</em> This kind of method is objective, can be replicated and repeated, and it collects numeric data.

I hope you find this information useful and interesting! Good luck!

8 0

3 years ago

A negative test charge experiences a force to the right as a result of an electric field. What is the best conclusion to draw ba

sergiy2304 [10]

Answer:

The electric field points to the left because the force on a negative charge is opposite to the direction of the field.

Explanation:

Normally,in an electric field, the positive charge has tendency to move from higher to lower potential and therefore, experience the electric force in the direction of electric field since electric field lines are directed from high to low potential whike a negative charge has tendency to move from low to high potential and hence experience the electric force in the direction opposite to electric field since electric field lines are directed from high to low potential.

Thus, we can say that; The electric field points to the left because the force on a negative charge is opposite to the direction of the field.

6 0

3 years ago