Let loudness be L, distance be d, and k be the constant of variation such that the equation that would best represent the given above is,
L = k/(d^2)
For Case 1,
L1 = k/(d1^2)
For Case 2,
L2 = k/((d1/4)^2)
For k to be equal, L1 = 16L2.
Therefore, the loudness at your friend's position is 16 times that of yours.
Answer:
h = 30.57 m
Explanation:
given,
angle made with horizon, θ= 27°
Length of the shadow,L = 60 m
now,
the height of the tree would be equal to
h = 60 x tan 27°
h = 30.57 m
hence, height of the tree is equal to 30.57 m
Answer:
Explanation:
Let the initial speed of the ball is given as
then angle of inclination is given as 33 degree
now its two components of velocity is given as
now the two positions with time given as
now when it hit the wall so we will have
now from above two equations we will have
now from above equations again