Answer:
-75.35°
Explanation:
Let C be the sum of the two vectors A and B. Hence, we can write the following

but since the vector C is in the -y direction,
= 0 and
= —12 m.
Thus
![B_{x} =-A_{x} =-[-Acos(180-127)]=(8)*cos(53)\\B_{x} =4.81m](https://tex.z-dn.net/?f=B_%7Bx%7D%20%3D-A_%7Bx%7D%20%3D-%5B-Acos%28180-127%29%5D%3D%288%29%2Acos%2853%29%5C%5CB_%7Bx%7D%20%3D4.81m)
similarly, we can determine
by rearranging equation (1)

so the magnitude of B is

Finally, the direction of B can be calculated as follows
Ф=
hence the vector B makes an angle of 75.35 clockwise with + x axis
Answer:
The tangential velocity for the cars are approximately 2.3 m/s
Explanation:
The given parameters are;
The radius of the Texas Star Ferris wheel, r = 65.8 mete secondsrs
The time it takes the Ferris wheel to go round once = 180 seconds
The angular velocity, ω = Change in angle rotated/(Time duration of the change)
ω = Δθ/Δt = 2·π/180
The tangential velocity for the cars,
= ω·r = 2 × 3.14/180 × 65.8 ≈ 2.3 m/s
The tangential velocity for the cars,
≈ 2.3 m/s.