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nekit [7.7K]
3 years ago
13

You're reading an article about forest fires in california and it features a photograph of firefighters battling a fire on a hil

lside next to a freeway. the firefighters are at the bottom of the hill using a firehose to control a fire that's in the middle of the hill. you're curious how fast the water is exiting the nozzle. analyzing the photograph in photoshop, you determine that the firehose nozzle is being held 2.1 m above the ground and is angled 43 ∘ above the horizontal. furthermore, the water from the hose lands on the hill 30 m from the feet of the firefighters. the article mentions that the grade of the hill is 37%, which corresponds to a slope of 20∘ above the horizontal. what is the speed the water when it exits the hose?

Physics
1 answer:
Lelechka [254]3 years ago
7 0
I will say it is about 20 m/s

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kozerog [31]

Answer:

5.15J

Explanation:

First. 54% of the 7kg refrigerant is liquid

So we find mass of vapour at inlet generator

M1 = ( 1-0.54)*7= 3.2kg

At compressor mass of vapour will be

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Its using

Q= mh

°= 3.5x 1.50×10^5 J/kg

=5.15J

4 0
3 years ago
A major contemporary learning view of personality which holds that personality traits result from a
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Answer:

21

Explanation:

21 is x because 211211 1 1 1 1  1aghh

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3 years ago
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A scientist is conducting research to determine how much pressure a dam can withstand. Why are good observations important to hi
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The things that a scientist should consider while observing the force is the environmental conditions,the force that is expected to act on the dam, the means to contain that force,  and compare different types of designs in accordance with the location of the dam

3 0
3 years ago
A model train engine was moving at a constant speed on a straight horizontal track. As the engine moved​ along, a marble was fir
bagirrra123 [75]

Answer:

The marble was moving in a projectile and the speed of the engine was 2.716 m/s

Explanation:

The vertical component of the marble's flight path relative to the train

is given by the equation y(t) = v*t - (4.9)*t^2,

where, v is the initial upward velocity of the marble relative to the train.  

So with y(1) = v - 4.9 = 0 we have  

v = 4.9 m/s.

The marble will reach maximum height after 0.5 seconds, at which the

height will be y(0.5) = (4.9)*(0.5) - (4.9)*(0.5)^2 = (4.9)*(0.25) = 1.225 m.

Now,  the marble has a vertical velocity component of 4.9 m/s and a horizontal velocity component

of V m/s such that tan(61) = 4.9 / V

V = 4.9 / tan(61) = 2.716 m/s

This horizontal velocity component of the marble is the same as the

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3 0
3 years ago
A helium atom (mass 4.0 u) moving at 598 m/s to the right collides with an oxygen molecule (mass 32 u) moving in the same direct
labwork [276]

Answer:

Speed of the helium after collision = 246 m/s

Explanation:

Given that

Mass of helium ,m₁ = 4 u

u₁=598 m/s

Mass of oxygen ,m₂ = 32 u

u₂  = 401 m/s

v₂ =445 m/s

Given that initially both are moving in the same direction and lets take they are moving in the right direction.

Speed of the helium after collision = v₁

There is no any external force on the masses that is why the linear momentum will be conserve.

Initial linear momentum = Final linear momentum

P = m v

m₁u₁+m₂u₂ = m₁v₁+m₂v₂

598 x 4 + 32 x 401 = 4 x v₁+ 32 x 445

v₁ = 246 m/s

Speed of the helium after collision = 246 m/s

6 0
3 years ago
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