The heat absorbed by the water is
Q = 500 (4.18) (32.2 - 25)
Q = 15048 J
The enthalpy of fusion of the sodium acetate is:
<span>ΔHf = Q / m
</span><span>ΔHf = 15048 / 100
</span>ΔHf = 150.48 J/g
The specific heat of the metal is 2.4733 J/g°C.
Given the following data:
- Initial temperature of water = 25.0°C
- Final temperature of water = 29.0°C
- Temperature of metal = 203.0°C
We know that the specific heat capacity of water is 4.184 J/g°C.
To find the specific heat of the metal (J/g°C):
Heat lost by metal = Heat gained by water.

Mathematically, heat capacity or quantity of heat is given by the formula;

<u>Where:</u>
- Q is the heat capacity or quantity of heat.
- m is the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
Substituting the values into the formula, we have:

Specific heat capacity of metal, c = 2.4733 J/g°C
Therefore, the specific heat of the metal is 2.4733 J/g°C.
Read more: brainly.com/question/18691577
Molar mass Na2CO3 = 106 g/mole
Using dimensional analysis:
0.787 moles Na2CO3 x 106 g/mole Na2CO3 = g Na2CO3
Answer = 83.4 g Na2CO3
Answer:
The density is 0,5 g/cm3
Explanation:
The density (δ) is the ratio between the mass and the volume of a compound:
δ=m/v= 3 g/6 cm3= <em>0,5 g/cm3</em>
Answer:

Explanation:
We are asked to find the new volume of a gas after a change in temperature. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

The gas was heated to 150 degrees Celsius and had a volume of 1587.4 liters.

The temperature was 100 degrees Celsius, but the volume is unknown.

We are solving for the volume at 100 degrees Celsius, so we must isolate the variable V₂. It is being divided by 100°C and the inverse of division is multiplication. Multiply both sides of the equation by 100°C.


The units of degrees Celsius cancel.



The original measurement of volume has 5 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 6 in the hundredth place to the right tells us to round to 2 up to a 3.

The volume of the gas at 100 degrees Celsius is approximately <u>1058.3 liters.</u>