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goldenfox [79]
3 years ago
11

Using a mass of 1.8 g and the volume displaced by the sample, calculate the sample's density. A) 0.17 g/mL B) 0.35 g/mL C) 0.60

g/mL D) 0.78g/mL
Physics
2 answers:
fomenos3 years ago
8 0
The answer to that probably would be C excuse me if I am wrong.
Anton [14]3 years ago
4 0

Answer:

Explanation:

The density of any element is calculated as:

d=\frac{m}{v}

Were d= density, m= mass and v=volume. Since we doesn't know the volume, lets do the calculation of the volume displaced for each option (a, b,c,d)

Clear m from the previous equation, so we have:

v=\frac{m}{d}

for a)

v=\frac{1.8}{0.17} =10.58 mL

for b)

v=\frac{1.8}{0.35} =5.14 mL

for c)

v=\frac{1.8}{0.6} =3 mL

for d)

v=\frac{1.8}{0.78} =2.3mL

So, just compare the given volume displaced match it with your density and that is the answer.

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The ideal gas law allows a scientist to calculate the number of moles that the other gas laws do not. The ideal gas law is given as

P V = n RT

rearranging the equation by dividing both side by "RT", we get

PV/(RT) = nRT/(RT)

n = PV/(RT)

inserting the values of pressure, volume and temperature, we get number of moles.

7 0
3 years ago
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When an object with a height of 0.10 meter is placed at a distance of 0.20 meter from a convex spherical mirror, the image will
goblinko [34]

Answer:

0.03 m

Explanation:

Mirrors work on the principle of reflection.

Reflection occurs when a ray of light hits a surface and bounces back into the origina medium at a different angle.

We can solve this problem by using the magnification equation:

\frac{y'}{y}=-\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

y = 0.10 m is the height of the object

p = 0.20 m is the distance of the object from the mirror

q = -0.06 m is the distance of the image from the mirror (negative because it appears behind the mirror, so it is a virtual image)

Solving for y', we find the size of the image:

y'=-\frac{q}{p}y=-\frac{-0.06}{0.20}(0.10)=0.03 m

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Paha777 [63]
Water and carbon dioxide
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At which position is the kinetic energy of a particle executing SHM greatest?
Over [174]

Explanation:

The kinetic energy of a particle in SHM is given by :

K=\dfrac{1}{2}m\omega^2(A^2-x^2)

Where

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The kinetic energy of a particle executing SHM is maximum at its equilibrium position and minimum at a maximum displacement from the equilibrium point.

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Svet_ta [14]

Answer:

0.8%

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