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goldenfox [79]
3 years ago
11

Using a mass of 1.8 g and the volume displaced by the sample, calculate the sample's density. A) 0.17 g/mL B) 0.35 g/mL C) 0.60

g/mL D) 0.78g/mL
Physics
2 answers:
fomenos3 years ago
8 0
The answer to that probably would be C excuse me if I am wrong.
Anton [14]3 years ago
4 0

Answer:

Explanation:

The density of any element is calculated as:

d=\frac{m}{v}

Were d= density, m= mass and v=volume. Since we doesn't know the volume, lets do the calculation of the volume displaced for each option (a, b,c,d)

Clear m from the previous equation, so we have:

v=\frac{m}{d}

for a)

v=\frac{1.8}{0.17} =10.58 mL

for b)

v=\frac{1.8}{0.35} =5.14 mL

for c)

v=\frac{1.8}{0.6} =3 mL

for d)

v=\frac{1.8}{0.78} =2.3mL

So, just compare the given volume displaced match it with your density and that is the answer.

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7 0
3 years ago
Read 2 more answers
A 6- F capacitor is charged to 90 V and is then connected across a 700- resistor. What is the initial charge on the capacitor
Lorico [155]

Answer:

540C.

Explanation:

A capacitor of capacitance C when charged to a voltage of V will have a charge Q given as follows;

Q = CV          ----------(i)

From the question, the initial charge on the capacitor is the charge on it before it was connected to the resistor. In other words, the initial charge on the capacitor will have a maximum value which can be calculated using equation (i) above.

Where;

C = 6F

V = 90V

Substitute these values into equation (i) as follows;

Q = 6 x 90

Q = 540 C

Therefore, the initial charge on the capacitor is 540C.

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3 years ago
in the diagram, the solid eventually becomes a gas. what will happen to bring the substance from a solid to a gas?
Gennadij [26K]
Sublimation is the answer

5 0
3 years ago
A 150kg motorcycle starts from rest and accelerates at a constant rate along a distance of 350m. The applied force is 250N and t
notsponge [240]

A) The net force on the motorbike is 205.9 N

B) The acceleration of the motorbike is 1.37 m/s^2

C) The final speed is 5.2 m/s

D) The elapsed time is 3.80 s

Explanation:

A)

There are two forces acting on the motorbike:

- The applied force, F = 250 N, forward

- The frictional force, F_f, backward

The frictional force can be written as

F_f = \mu mg

where

\mu=0.03 is the coefficient of kinetic friction

m=150 kg is the mass of the motorbike

g=9.8 m/s^2 is the acceleration of gravity

Therefore the net force is given by

\sum F = F - F_f = F - \mu mg

And substituting, we find

\sum F=250 - (0.03)(150)(9.8)=205.9 N

2)

The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:

\sum F = ma

where

m is the mass

a is the acceleration

In this problem, we have

\sum F = 205.9 N is the net force

m = 150 kg is the mass

Solving for a, we find the acceleration:

a=\frac{\sum F}{m}=\frac{205.9}{150}=1.37 m/s^2

C)

Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For this motorbike, we have:

u = 0 (it starts from rest)

a=1.37 m/s^2

s = 350 m

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(1.37)(9.8)}=5.2 m/s

4)

For this part of the problem, we can use the following suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the elapsed time

Here we have:

v = 5.2 m/s

u = 0

a=1.37 m/s^2

Solving for t, we find

t=\frac{v-u}{a}=\frac{5.2-0}{1.37}=3.80 s

Learn more about Newton's laws of motion and accelerated motion:

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#LearnwithBrainly

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- Which of the following cannot be a unit for work?<br>A. Joule <br>B. N.m<br>C. Kilowatt<br>D. All​
shusha [124]

Answer:

joule

Explanation:

is for work it is also repreasent by SI

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