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kap26 [50]
3 years ago
8

According to the Holland Codes, which career is best suited to someone who scored highest in the investigative category?

Physics
1 answer:
Yuri [45]3 years ago
8 0
<span>Laboratory chemist working on cancer research.</span>
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You charge an initially uncharged 65.7-mf capacitor through a 39.1-Ï resistor by means of a 9.00-v battery having negligible int
uysha [10]
In a RC-circuit, with the capacitor initially uncharged,  when we connect the battery to the circuit the charge on the capacitor starts to increase following the law:
Q(t) = Q_0 (1-e^{-t/\tau})
where t is the time, Q_0 = CV is the maximum charge on the capacitor at voltage V, and \tau = RC is the time constant of the circuit.
Using this law, we can answer all the three questions of the problem.

1) Using R=39.1 \Omega and C= 65.7 mF=65.7\cdot 10^{-3}F, the time constant of the circuit is:
\tau = RC=(39.1 \Omega)(65.7 \cdot 10^{-3}F)=2.57 s

2) To find the charge on the capacitor at time t=1.95 \tau, we must find before the maximum charge on the capacitor, which is
Q_0 = CV=(65.7 \cdot 10^{-3}F)(9 V)=0.59 C
And then, the charge at time t=1.95 \tau is equal to
Q(1.95 \tau) = Q_0 (1-e^{-t/\tau})=(0.59 C)(1-e^{-1.95})=0.51 C

3) After a long time (let's say much larger than the time constant of the circuit), the capacitor will be fully charged, this means its charge will be Q_0 = 0.59 C. We can see this also from the previous formule, by using t=\infty:
Q(t) = Q_0 (1-e^{-\infty})=Q_0(1-0) = 0.59 C

4 0
3 years ago
What is the current
Art [367]

Answer:

2.5mA

Explanation:

In the picture.

I think it's a clear.

8 0
3 years ago
Which skateboarder has greater momentum?
Verizon [17]

Answer:

skateboard b

Explanation:

p=mv

skateboard a

p=(60kg)(1.5m/s)=90kg*m/s

skateboard b

p=(50kg)(2m/s)=100kg*m/s

5 0
3 years ago
Rachel hits a golf ball into the air. What type of motion is the ball's path?
sladkih [1.3K]

Answer:

omg

the ground is BREAKING

Explanation:

5 0
2 years ago
A gyroscope slows from an initial rate of 32.0 rad/s at a rate of 0.700 rad/s2. How long does it take to come to rest? How many
Darya [45]

Answer:

t=45.7s

\alpha =116revolutions

Explanation:

Since we have given values of ω₀=32.o rad/s ,ω=0 and α=-0.700 rad/s² to find t we use below equation

w=w_{o}+at\\  0=(32.0rad/s)+(-0.700rad/s^{2} )t\\t=\frac{-32.0}{-0.700} \\t=45.7s

To find revolutions we use below equation

w^{2}=w_{o}^{2}+2a\alpha

Substitute the given values to find revolutions α

So

0=(32.0rad/s)^{2}+2(-0.700rad/s^{2} )\alpha  \\\alpha =\frac{(-32.0rad/s)^{2}}{2(-0.700rad/s^{2} )} \\\alpha =731rad

To convert rad to rev:

\alpha =(731rad)*(\frac{1rev}{2\pi rad} )\\\alpha =116revolutions

7 0
3 years ago
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