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valina [46]
3 years ago
11

Which of these is an element?

Chemistry
2 answers:
Yanka [14]3 years ago
6 0

Answer:

A.

Explanation:

The rest are molecules and/or compounds

just olya [345]3 years ago
3 0
B
Sksnksnsksksksksksksks
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A student heats 10.52 g of sodium hydrogen carbonate in a crucible until the compound completely decomposes to sodium carbonate
saveliy_v [14]

Answer:

m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

Explanation:

Hello!

In this case, since the decomposition of sodium hydrogen carbonate is:

2NaHCO_3(s)\rightarrow Na_2CO_3(s)+H_2O(g)+CO_2(g)

Thus, since there is a 2:1 mole ratio between the sodium hydrogen carbonate and sodium carbonate, and the molar masses are 84.01 and 105.99 g/mol respectively, we obtain the following theoretical yield:

m_{Na_2CO_3}^{theoretical}=10.52gNaHCO_3*\frac{1molNaHCO_3}{84.01gNaHCO_3}*\frac{1molNa_2CO_3}{2molNaHCO_3}  *\frac{105.99gNa_2CO_3}{1molNa_2CO_3}\\\\ m_{Na_2CO_3}^{theoretical}=6.636gNa_2CO_3

Best regards!

4 0
2 years ago
How many atoms are in 2.45 moles of hydrogen
allochka39001 [22]

Answer:

There are 1.4754246675000002e+24 atoms of Hydrogen within the measurement of 2.45 moles of hydrogen!

Explanation:

6 0
3 years ago
Mg+o2 balanced eaquation
Tanya [424]

Answer:

2Mg+O2=2MgO

balanced equation

hope it helps.

5 0
3 years ago
Read 2 more answers
Please help! Which Zeros are significant in the measurement .0506010 kg?
Vitek1552 [10]
It would be a,b,c as the answer. hope this helps!
7 0
2 years ago
The Hall process for the production of aluminum involves the reaction of aluminum oxide with elemental carbon to give aluminum m
topjm [15]

Answer:

  • <u><em>1.7 × 10³ kg of ore.</em></u>

Explanation:

Call X the amount of aluminum ore mined to produce 1.0 × 10³ kg the aluminum metal.

Then, taking into account the yield of the reaction (82 % = 0.82) and the percent of aluminun in the ore (71% = 0.71), you can write the following equation:

  •  X         ×          71%                ×       82%     =     1.0 × 10³ kg

         ↑                      ↑                              ↑                     ↑

(mass of ore)    (% of Al in the ore)        (yield)        ( Al metal to obtain)

You must just simplify, solve and compute:

  • 0.71 × 0.82 × X = 1,000
  • X = 1,000 / (0.71 × 0.82) = 1,000 / 0.5822 = 1,717.6 Kg

Round to two significant figures; 1,700 kg = 1.7 × 10³ kg of ore ← answer.

6 0
3 years ago
Read 2 more answers
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