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Tanzania [10]
3 years ago
11

& For the reaction A

Chemistry
1 answer:
iVinArrow [24]3 years ago
5 0

Answer:

The rate reduces by a factor cf /2.

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3. What is the easiest way to create electron configurations?
jarptica [38.1K]

Answer:

To calculate an electron configuration, divide the periodic table into sections to represent the atomic orbitals, the regions where electrons are contained. Groups one and two are the s-block, three through 12 represent the d-block, 13 to 18 are the p-block and the two rows at the bottom are the f-block.Explanation:

6 0
3 years ago
Which statement is true of diffusion?
raketka [301]

Answer:

Molecules move from areas of high concentration to areas of low concentration.

4 0
3 years ago
To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, how many moles of nitrogen gas (n2) are required?
evablogger [386]

To completely convert 9. 0 moles of hydrogen gas (h2) to ammonia gas, 3.0 moles of nitrogen gas (n2) are required.

<h3>What are moles?</h3>

The mole is a SI unit of measurement that is used to calculate the quantity of any substance.

<h3 />

The given reaction is \rm  N_2(g) + 3H_2(g) \rightarrow 2NH_3(g)

By the stoichiometry rule of ratio hydrogen: nitrogen

3 : 1

The reacted moles of nitrogen is equals to H/3 moles of reacted hydrogen

So, moles of nitrogen  

\rm Moles\; of\; nitrogen = \dfrac{9.0 }{3} =3.0\;mol

Thus, 3.0 moles of nitrogen gas (n2) are required.

Learn more about moles

brainly.com/question/26416088

#SPJ4

3 0
2 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 3.50 moles of magnesium
Firdavs [7]

Answer:

n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO

Best regards!

3 0
3 years ago
Lithium β is a solid phase of lithium still unknown to science. The only difference between it and ordinary lithium is that Lith
pychu [463]

Answer:

The density of Lithium β is 0.5798 g/cm³

Explanation:

For a face centered cubic (FCC) structure, there are total number of 4 atoms in the unit cell.

we need to calculate the mass of these atoms because density is mass per unit volume.

Atomic mass of Lithium is 6.94 g/mol

Then we calculate the mass of four atoms;

= 4 .atoms*\frac{1.mole}{6.022 X10^{23} .atoms} *\frac{6.94g}{mole} = 4.6097 X10^{-23} g

⇒next, we estimate the volume of the unit cell in cubic centimeter

given the edge length or lattice constant a = 0.43nm

a = 0.43nm = 0.43 X 10⁻⁹ m = 0.43 X 10⁻⁹ X 10² cm = 4.3 X 10⁻⁸cm

Volume of the unit cell = a³ = (4.3 X 10⁻⁸cm)³ = 7.9507 X 10⁻²³ cm³

⇒Finally, we calculate the density of Lithium β

Density = mass/volume

Density = (4.6097 X 10⁻²³ g)/(7.9507 X 10⁻²³ cm³)

Density = 0.5798 g/cm³

3 0
3 years ago
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