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3 years ago

Atoms of which types of elements tend to gain electrons? Atoms of which types of elements tend to lose electrons?

1 answer:

8 0

Atoms of elements that are nonmetals tend to gain electrons and atoms of metallic elements tend to lose electrons. Metals have few electrons in their valence shells. By losing those electrons, these metals achieve noble gas configuration and satisfy the octet rule. Nonmetals that have close to 8 electrons in their valence shells readily accept electrons to achieve noble gas configuration. An example is the reaction between calcium and oxygen. Calcium is a metal and has 2 valence electrons. Oxygen is a nonmetal and has 6 valence electrons. Calcium gives up its two valence electrons and oxygen accepts them and an ionic bond is established resulting in the formation of anew compound namely calcium oxide.

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When a potassium ion (K+) moves from the soil into the vacuole of a cell on the surface of a root, it must pass through several

insens350 [35]

<h3><u>Answer;</u></h3>

C) primary cell wall → plasma membrane → cytoplasm → vacuole

<h3><u>Explanation;</u></h3>

The cell wall is the protective outer layer of a plant cell, that gives the cell strength and structure, and also filters molecules that pass in and out of the cell.
Cell membrane acts as a semi-permeable barrier separating the inside of the cell from the outside of the cell. The membrane allows regulation of what enters/exits the cell and how quickly.
Cytoplasm is the jelly-like fluid that fills a cell. It is responsible for giving a cell its shape and also helps to fill out the cell and keeps organelles in their place.
Vacuoles are membrane-bound sacs within the cytoplasm of a cell that function in several different ways. They functional in providing structural support, as well as serving functions such as storage, waste disposal, protection, and growth.
<u>Potassium ion from the extracellular environment will move to the cell vacuole via the cell wall, the cell membrane and then via the cytoplasm to the vacuole.</u>

4 0

3 years ago

A sample of aluminum, which has a specific heat capacity of 0.897·J·g−1°C^−1 , is put into a calorimeter (see sketch at right) t

Tcecarenko [31]

Answer: The mass of aluminium sample is 55.4 gram

Explanation:

$Q_{absorbed}=Q_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$

where,

$m_1$ = mass of aluminium = ?

$m_2$ = mass of water = 300.0 g

$T_{final}$ = final temperature = $23.8^0C$

$T_1$ = temperature of aluminium = $94.5^oC$

$T_2$ = temperature of water = $21.0^oC$

$c_1$ = specific heat of aluminium = $0.897J/g^0C$

$c_2$ = specific heat of water = $4.184J/g^0C$

Now put all the given values in equation (1), we get

$-[m_1\times c_1\times (T_{final}-T_1)]=[m_2\times c_2\times (T_{final}-T_2)]$

$-[m_1\times 0.897\times (23.8-94.5)^0C]=[300.0g\times 4.184\times (23.8-21.0)]$

$m_1=55.4g$

Therefore, the mass of aluminium sample is 55.4 gram

8 0

3 years ago

if a geologist found two fossils of different species buried next to each other in a rock layer, he or she might hypothezise tha

vaieri [72.5K]

This would be true.

The reason why this answer would be true is because a fossil's position in the rock layers determine how long they died and were preserved. If the fossils were right next to each other, then that means both organisms were preserved at the same time.

5 0

3 years ago

Which of the following is a chemical property?

ad-work [718]

The first one is D hope it helps!

6 0

2 years ago

Read 2 more answers

If 45.0 mL of ethanol (density =0.789g/mol) initially at 6.0°C mix with 45.0 mL of water (density =1.0 g/mol) initially at 28.0°

Likurg_2 [28]

The final temperature of the mixture : 21.1° C

<h3>Further explanation </h3>

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released

Q in(gained) = Q out(lost)

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

Q ethanol=Q water

mass ethanol=

$\tt mass=\rho\times V\\\\mass=0.789\times 45=35.505~g$

mass water =

$\tt mass=1~g/ml\times 45~ml=45~g$

then the heat transfer :

$\tt 35.505\times 2.42~J/g^oC\times (t-6)=45\times 4.18~J/g^oC\times (28-t)\\\\85.922t-515.533=5266.8-188.1t\\\\274.022t=5782.33\rightarrow t=21.1^oC$

5 0

2 years ago