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Sedbober [7]
4 years ago
6

A train's mass is 500 kg and it's acceleration is 5 m/s. What is the net force on the train

Physics
1 answer:
trapecia [35]4 years ago
7 0
The answer is 2500 newtons. F = M * A, so 500 kg x 5 m/s = 2500 newtons.
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NHT0015
poizon [28]

Answer:

(1) 1×10⁻⁴

Explanation:

From the question,

α = (ΔL/L)/(ΔT)............. Equation 1

Where α = linear expansivity of the metal plate, ΔL/L = Fractional change in Length, ΔT = Rise in temperature.

Given: ΔL/L = 1×10⁻⁴, ΔT = 10°C

Substitute these values into equation 1

α  = 1×10⁻⁴/10

α = 1×10⁻⁵ °C⁻¹ .

β = (ΔA/A)/ΔT................... Equation 2

Where β = Coefficient of Area expansivity, ΔA/A = Fractional change in area.

make ΔA/A the subject of the equation

ΔA/A = β×ΔT.......................... Equation 3

But,

β = 2α.......................... Equation 4

Substitute equation 4 into equation 3

ΔA/A = 2α×ΔT................ Equation 5

Given: ΔT = 5°C, α = 1×10⁻⁵ °C⁻¹

Substitute into equation 5

ΔA/A = ( 2)×(1×10⁻⁵)×(5)

ΔA/A  = 10×10⁻⁵

ΔA/A  = 1×10⁻⁴

Hence the right option is (1) 1×10⁻⁴

3 0
3 years ago
Consider a turnbuckle that has been tightened until the tension in wire AD is 350 N. Draw the FBD that is required to determine
Mars2501 [29]

Answer:

yes

Explanation:

yes

6 0
3 years ago
A three-way 120 V lamp bulb that contains two filaments is rated for 100-200-300 W. One filament burns out. Afterward, the bulb
ololo11 [35]

Answer:

The larger resistance value is 144 ohms and the smaller resistance value is 48 ohms.

Explanation:

Given that Resistance, R, is inversely proportional to Power, the largest value of power will yield the smallest value of resistance and vice versa.

The largest value of resistance will be:

P = V²/R

R = V²/P

R = 120²/100

R = 144 ohms

The smallest value of resistance will be:

R = 120²/300

R = 48 ohms

8 0
4 years ago
An object is moving with an initial velocity of 9m/s. It accelerates at a rate 1.5m/sec2 over a distance of 20m. What is it’s ne
puteri [66]

Answer:

11.87

Explanation:

final velocity^2= initial velocity ^2+ 2* Acceleration* distance

Final Velocity^2= 9*9+2*1.5.20

final velocity^2 = 141

final velocity = 11.87

4 0
4 years ago
One point charge has a magnitude 5.4x10-7 C. A second charge 0.25 meters away has a magnitude of 1.1x10-17 C. What is the electr
choli [55]

The electric force on the charges will be equal and opposite in nature and the magnitude will be 8.5536 × 10⁻¹³ Newton.

Formula for electrostatic force is F = ( K q1 q2 )/ r²

where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.

In question we have given

value of q1 = 5.4 x 10⁻⁷ C

value of q2 = 1.1 x 10⁻¹⁷ C

distance between the (r) = 0.25 m

Applying the formula

F = ( K x (5.4 x 10-7) x (1.1x10-17) )/ 0.25²

F = ( (9 × 10⁹ ) x (5.4 x 10-7) x (1.1x10-17) )/ 0.25²

F = ( (9 × 5.4 × 1.1) × ( 10⁹ × 10⁻⁷ x 10⁻¹⁷) )/ ( 6.25 × 10⁻² )

F = ( 53.46 × 10⁻¹⁵) / ( 6.25 × 10⁻² )

F = 8.5536 × 10⁻¹³ Newton

Electrostatic force = 8.5536 × 10⁻¹³ Newton

So, The point charges are possessing equal and opposite electrostatic force of magnitude 8.5536 × 10⁻¹³ Newton.

Learn more about Electrostatic Force here:

brainly.com/question/23121845

#SPJ10

8 0
2 years ago
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