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1 answer:
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Answer:
8 Hz, 48 Hz
Explanation:
The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.
The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by
where
is the fundamental frequency
In this problem, we know that the wave's third harmonic has a frequency of
This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:
Now we can also find the frequency of the 6-th harmonic using n = 6:
Answer:
Fundamental frequency is 70.12 m
Explanation:
For an open organ pipe, the fundamental frequency is given by :
n = 1 for fundamental frequency
v is speed of sound in air, v = 345 m/s
l is length of open organ pipe, l = 2.46 m
Substituting values in above formula. So,
So, the fundamental frequency of this pipe is 70.12 m.
π=iMRT
Where, π is Osmotic pressure,
i=1 for non-electrolytes,
M is molar concentration of dissolved species (units of mol/L)
R is the ideal gas constant = 0.08206 L atm mol⁻¹K⁻¹,
T is the temperature in Kelvin(K),
Here, to calculate M convert into standard units mg tog, ml to L, c to Kelvin
M= ( *10⁻³ )/ 0.175 =(5.987 *10⁻⁵)mol / 0.175L = 34.21*10⁻⁵ mol/L
π=iMRT=(1)*(34.21*10⁻⁵)*(0.08206)*(298.15)=837×10⁻⁵= 8.37×10⁻³ atm
=6.36 torr
(1 atm=760 torr, 1 Kelvin =273.15 °C, 1L=1000ml, 1g=1000mg)