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3 years ago

A golf ball rolls up a hill toward a miniature-golf hole. Assume the direction toward the hole is positive.

Physics

1 answer:

umka21 [38]3 years ago

4 0

Answer:

a) 1m/s

b) -1m/s

Explanation:

So the ball starts rolling up the hill with a speed of 2m/s (v0=2m/s) and it decelerates at a constant rate of 0.5 m/s2 (a = -0.5 m/s², minus because it decelerates).

Now, the equation for calculating velocity is:

v = v0 + a • t, where t represents time

So, ball's velocity after 2 seconds is:

v = 2m/s + (-0.5m/s²• 2s)

v = 2m/s + (-1m/s)

v = 1m/s

We use the same formula for finding ball's velocity after 6 seconds:

v = v0 + a • t

v = 2m/s + (-0.5m/s² • 6s)

v = 2m/s + (-3m/s)

v = -1m/s

Of course, velocity can't be negative, this only means that the ball moves in 1m/s velocity, only in opposite direction (downhill).

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Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

Zarrin [17]

Answer:

$\rm 9.186\times 10^{-7}\ C.$

Explanation:

Given:

Diameter of the plates of the capacitor, D = 21 cm = 0.21 m.
Distance of separation between the plates, d = 1.0 cm = 0.01 m.
Minimum value of electric field that produces spark, $\rm E=3\times 10^6\ N/C.$

When the dimensions of the plate of the capacitor is comparatively much larger than the distance of separation between the plates, then, according to the Gauss' law of electrostatics, the value of the electric field strength in the region between the plates of the capacitor is given by

$\rm E=\dfrac{\sigma}{\epsilon_o}.$

where,

$\rm \sigma$ = surface charge density of the plate of the capacitor = $\dfrac qA$ .

$\rm q$ = magnitude of the charge on each of the plate.
$\rm A$ = surface area of each of the plate = $\rm \pi \times (Radius)^2=\pi \times\left ( \dfrac{D}{2}\right )^2= \pi \times \left ( \dfrac{0.21}{2}\right )^2=3.46\times 10^{-2}\ m^2.$
$\epsilon_o$ = electrical permittivity of free space, having value = $8.85\times 10^{-12}\rm \ C^2N^{-1}m^{-2}.$

For the minimum value of electric field that produces spark,

$\rm E = \dfrac{q}{A\epsilon_o}\\\Rightarrow q = E\ A\epsilon_o\\=3\times 10^6\times 3.46\times 10^{-2}\times 8.85\times 10^{-12}\\=9.186\times 10^{-7}\ C.$

It is the maximum value of the magnitude of charge which can be added up to each of the plates of the capacitor.

4 0

3 years ago

A politician running for office tells a crowd at a rally that the only way to keep the food chain safe is to stop allowing the g

olasank [31]

Answer:

B. No. He presented no scientific data to support his claim.

6 0

3 years ago

Convert 3402kgm/s to 20000Newtons

oee [108]

The 3,402 has units of kg-m/s. That's momentum. The 20,000 has units of Newtons. That's force. Momentum and force are different physical things, and you can't convert them from one to the other.

The best I can do for you is something like this:

Let's say you have a moving object with 3,402 kg-m/s of momentum, and you want to STOP it completely. You want to stand in front of it and push back on it, hard enough and for long enough to CHANGE its momentum from 3,402 kg-m/s to zero.

Also ... there's a limit to how hard you can push. The most force you can exert is 20,000 Newtons.

The amount you'll change its momentum is called the impulse you give it. The quantity of impulse is (force) x (length of time you push on it).

So you need to keep pushing it back for (T seconds) long enough so that

(20,000 Newtons of force) x (T seconds) = 3,402 kg-m/s of momentum .

Divide each side of that equation by (20,000 Newtons). Then it says:

(T seconds) = (3,402 kg-m/s) / (20,000 Newtons)

T = 0.1701 second

And that's how you provide just enough impulse to stop the flying object ... push on it with 20,000 Newtons of force for exactly 0.1701 second, and it loses all its momentum and falls out of the air onto the ground at your feet.

This story is the closest I can come to anything that looks like "convert"ing momentum into force.

3 0

3 years ago

Can someone please help me ASAP!

Artist 52 [7]

I’m not 100% sure but i think it’s A because if you divide the speed by the time you get 2 and also all the other answer choices don’t make any sense!

3 0

3 years ago

A go-cart is traveling at a rate of 25 m/sec for 20 seconds. How far will the go cart travel?

notsponge [240]

Answer:

Distance travel by go-cart = 500 meter

Explanation:

Given:

Speed of go cart = 25 m/s

Time travel = 20 seconds

Find:

Distance travel by go-cart

Computation:

Distance = Speed x time

Distance travel by go-cart = Speed of go cart x Time travel

Distance travel by go-cart = 25 x 20

Distance travel by go-cart = 500 meter

4 0

2 years ago