The earth axis to tilt and orbits the sun
Answer
given,
mass of glider = 0.23 Kg
spring constant = k = 4.50 N/m
spring stretched to 0.130 m
The springs potential energy =
![U = \dfrac{1}{2}kx^2](https://tex.z-dn.net/?f=U%20%3D%20%5Cdfrac%7B1%7D%7B2%7Dkx%5E2)
![U = \dfrac{1}{2}\times 4.5 \times 0.13^2](https://tex.z-dn.net/?f=U%20%3D%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%204.5%20%5Ctimes%200.13%5E2)
U = 0.038 J
at x = 0,the only energy will be kinetic .
![\dfrac{1}{2}mv^2=0.038](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%3D0.038)
![\dfrac{1}{2}\times 0.23 \times v^2=0.038](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%200.23%20%5Ctimes%20v%5E2%3D0.038)
v² = 0.3304
v = 0.575 m/s
displacement of the glider
using conservation of energy
![\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2](https://tex.z-dn.net/?f=%20%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%3D%5Cdfrac%7B1%7D%7B2%7Dkx%5E2)
![x =v\sqrt{\dfrac{m}{k}}](https://tex.z-dn.net/?f=%20x%20%3Dv%5Csqrt%7B%5Cdfrac%7Bm%7D%7Bk%7D%7D)
![x =3\times \sqrt{\dfrac{0.23}{4.5}}](https://tex.z-dn.net/?f=%20x%20%3D3%5Ctimes%20%5Csqrt%7B%5Cdfrac%7B0.23%7D%7B4.5%7D%7D)
x = 0.678 m
M = mass of the whale = 1000 kg
m = mass of the seal = 200 kg
V = initial velocity of whale before collision with the seal = 6.0 m/s
v = initial velocity of the seal before collision with the whale = 0 m/s
V' = final velocity of two sea creatures after collision = ?
Using conservation of momentum
M V + m v = (M + m) V'
inserting the above values in the equation
(1000 kg) (6.0 m/s) + (200 kg) (0 m/s ) = (1000 kg + 200 kg) V'
6000 kgm/s + 0 kgm/s = (1200 kg) V'
V' = (6000 kgm/s ) /(1200 kg)
V' = 5 m/s