Review please help.
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Answer:
Explanation:
Energy of signal being radiated per second on all sides = 71 x 10³ J .
At a distance of 220 m it is spread over an area of 4 π x (220)² because it is spreading uniformly on all sides.
So energy crossing per unit area
=
= 11.67 x 10⁻² Wm⁻²s⁻¹.
This is the intensity of the signal.
At 2200 m this intensity will further reduce by 100 times
So there it becomes equal to
11.67 x 10⁻⁴ Wm⁻² s⁻¹.
Here in order to find out the distance between two planes after 3 hours can be calculated by the concept of relative velocity
here
speed of first plane is 700 mi/h at 31.3 degree
speed of second plane is 570 mi/h at 134 degree
now the relative velocity is given as
now the distance between them is given as
so the magnitude of the distance is given as
miles
so the distance between them is 2985.6 miles