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3 years ago

Balance the equation αC6H14(g)+βO2(g)→γCO2(g)+δH2O(g)

2 answers:

7 0

Answer: The balanced reaction is:
<span>2 C6H14(g)+ 19 O2(g) → 12 <span>CO2</span>(g)+ 14 H2O(g)

Note: While balancing the chemical reaction, care must be taken that total number atoms (of each type) on both reactant and product side must be same. In present case, there are 12 'C' atoms, 28 'H' atoms and 38 'O' atoms on both reactant and product side. Hence, the reaction is balanced. </span>

Leona [35]3 years ago

3 0

$2 \ C_6H_{14}_{(g)} + 19 \ O_2_{(g)} \rightarrow 12 \ CO_2_{(g)} + 14 \ H_2O_{(g)}$

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13. Mercury has one of the lowest heat capacities. If 257J of heat are added to 5500g of mercury,the mercury's temp will increas

NikAS [45]

Given:

257J of heat

5500g of mercury

increase by 5.5 degrees Celsius

Required:

Specific heat of mercury

Solution:

H = mCpT

257J = (5500g of mercury) Cp (5.5 degrees Celsius)

Cp = 8.5 x 10^-3 Joules per gram per degree Celsius

3 0

3 years ago

4. What is a homogeneous solution? Give an example.

Gennadij [26K]

Answer:

Homogeneous solutions are solutions with uniform composition and properties throughout the solution.

Explanation:

For example a cup of coffee, perfume, cough syrup, a solution of salt or sugar in water, etc. Heterogeneous solutions are solutions with non-uniform composition and properties throughout the solution.

8 0

2 years ago

Read 2 more answers

If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?

valkas [14]

Answer: the pH of the solution is 4.52

Explanation:

Consider the weak acid as Ha, it is dissociated as expressed below

HA H⁺ + A⁻

the Henderson -Haselbach equation can be expressed as;

pH = pKa + log( [A⁻] / [HA])

the weak acid is dissociated into H⁺ and A⁻ ions in the solution.

now the conjugate base of the weak acid HA is

HA(aq) {weak acid} H⁺(aq) + A⁻(aq) {conjugate base}

so now we calculate the value of Kₐ as well as pH value by substituting the values of the concentrations into the equation;

pKₐ = -logKₐ

pKₐ = -log ( 7.4×10⁻⁵ )

pKₐ = 4.13

now thw pH is

pH = pKₐ + log( [A⁻] / [HA])

pH = 4.13 + log( [0.540] / [0.220])

pH = 4.13 + 0.3899

pH = 4.5199 = 4.52

Therefore the pH of the solution is 4.52

6 0

3 years ago

An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam

MAXImum [283]

Explanation:

The given data is as follows.

Mass of mixture = 0.3471 g

As the mixture contains oxalic acid and benzoic acid. So, oxalic acid will have two protons and benzoic acid has one proton.

This means oxalic acid will react with 2 moles of NaOH and benzoic acid will react with 1 mole of NaOH.

Hence, moles of NaOH in 97 ml = $\frac{0.1090 \times 97}{1000}$

= $10.573 \times 10^{-3} mol$

Moles of HCl in 21.00 ml = $\frac{0.2060 \times 21}{1000}$

= $4.326 \times 10^{-3}$ mol

Therefore, total moles of NaOH that reacted are as follows.

$10.573 \times 10^{-3} mol$ - $4.326 \times 10^{-3} mol$

= $6.247 \times 10^{-3}$ mol

So, total 3 mole of NaOH will react with 1 mole of mixture. Therefore, number of moles of NaOH reacted with benzoic acid is as follows.

$\frac{6.247 \times 10^{-3}}{3}$

= $2.082 \times 10^{-3}$ mol

Since, molar mass of NaOH is 40 g/mol. Therefore, calculate the mass of NaOH as follows.

$2.082 \times 10^{-3} mol \times 40 g/mol$

= $83.293 \times 10^{-3}$ g

= 0.0832 g

Whereas molar mass of benzoic acid is 122 g/mol.

Therefore, 40 g NaOH = 122 g benzoic acid

So, 0.0832 g NaOH = $\frac{122 g}{40 g} \times 0.0832 g$

= 0.253 g

Hence, calculate the % mass of benzoic acid as follows.

$\frac{0.253 g}{0.3471 g} \times 100$

= 73.10%

Thus, we can conclude that mass % of benzoic acid is 73.10%.

4 0

3 years ago

Part D

qwelly [4]

Answer:

Explanation:

The number on the top right of the symbol shows ATOMIC NUMBER , if it is written alone only one digit or number overall .

And if the number is also in bottom left then bottom left number will be ATOMIC NUMBER and top right will be MASS NUMBER

Hope this will help you *-*

7 0

3 years ago