Answer:
A) move into the left lane to pass the motorcycle
Explanation:
According to law, when it is needed to pass other vehicles, it requires you to only pass other vehicles on the left (using the left lane).
When passing a motorcyclist, remember to give him/her the same full lane width as other vehicles. Never drive in the same lane with a motorcyclist, even if the lane is wide enough to fit your vehicle and the motorcyclist.
0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.
Answer: Option B
<u>Explanation:</u>
Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any

The orbit’s period is given by,

Where,
= Earth’s period
= planet’s period
= sun’s mass
= earth’s radius
Now,

As, planet mass is equal to 0.7 times the sun mass, so

Taking the ratios of both equation, we get,





Given
and 


Answer:
protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons
Explanation:
mass number: the sum of the number of protons and
neutrons in an atom
this is key as it explains that protons+neutrons= mass number, so if the mass number is 13 and protons are 6 its 13-6=7 neutrons
h, it has the lowest density so it makes sense it is the gas.