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3 years ago

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4. State in words how acceleration is calculated.

1 answer:

dimaraw [331]3 years ago

4 0

You multiply force times friction

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By how much does the gravitational potential energy of a 54-kg pole vaulter change if her center of mass rises about 4.0 m durin

kodGreya [7K]

<span>the gravational potential energy of anything on the ground is zero. When calculating potential energy you take height in meters and multiply it by the mass of the object in kilograms and the acceleration of gravity to get a new unit called Joules. Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.</span>

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3 years ago

Read 2 more answers

. If a pendulum-driven clock gains 5.00 s/day, what fractional change in pendulum length must be made for it to keep perfect tim

inn [45]

Answer:

The appropriate response will be "Length must be increased by 0.012%".

Explanation:

The given values is:

ΔT = 5 s/day

Now,

⇒ $\frac{\Delta T}{T} =\frac{5}{24\times 60\times 60}$

On multiplying both sides by "100", we get

⇒ $\frac{\Delta T}{T}\times 100 =\frac{500}{24\times 60\times 60}$

⇒ $\frac{\Delta T}{T}\times 100=0.005787$ (%)

∵ $T=2\pi\sqrt{\frac{l}{g} }$

On substituting the values, we get

⇒ $\frac{\Delta T}{T}$ % = $\frac{1}{2}\times \frac{\Delta l}{l}$ %

On applying cross multiplication, we get

⇒ $\frac{\Delta l}{l}$ % = $2\times \frac{\Delta T}{T}$ %

⇒ = $2\times 0.05787$

⇒ = $0.011574$

⇒ = $0.012$ %

6 0

3 years ago

The corpus callosum is comprised of more than 200 million axons that connect the hemispheres of the brain. Please select the bes

mamaluj [8]

Hello, love! The answer is True, or T, on Edge2020.

Hope this helped!

~ V.

8 0

3 years ago

Read 2 more answers

Volume can be measured in: <br>A. cubic centimeters. <br>B. centimeters. <br>C. square centimeters.

Ad libitum [116K]

Answer-

A. cubic centimeters.

Hope this helps!

8 0

3 years ago

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The work done to compress a spring with a force constant of 290.0 N/m a total of 12.3 mm is: a) 3.57 J b) 1.78 J c) 0.0219 J d)

iren2701 [21]

Answer:

Work done, W = 0.0219 J

Explanation:

Given that,

Force constant of the spring, k = 290 N/m

Compression in the spring, x = 12.3 mm = 0.0123 m

We need to find the work done to compress a spring. The work done in this way is given by :

$W=\dfrac{1}{2}kx^2$

$W=\dfrac{1}{2}\times 290\times (0.0123)^2$

W = 0.0219 J

So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.

7 0

4 years ago