3 years ago

Please need some help understanding this

1 answer:

4 0

This type of problem is known to be the rate of decay or decomposition. In dealing with this type of problem, we would let Q to be the amount present at any time, Qo as the initial amount, k as the rate constant and then t as the number of hours to reduce the initial amount to the present amount. The equation would be Q=Q0 times e^ -kt.

In letter a, the answer would be 98.7389 seconds. Meanwhile in letter b the answer is 125.8548 seconds.

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