Tobias has 12 coins in his pocket. Of these coins, 8 were made in the year 2000,and

The length of the red line segment is 8, and the length of the blue line segment is 4. How long is the major axis of the ellipse

inessss [21]

Answer: the answer is

C. 12

5 0

3 years ago

If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.

oksian1 [2.3K]

Answer:

$NK = 15$

$JL = 26$

$KL = 19.85$

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

Step-by-step explanation:

Given

$MK = 30$

$NL = 13$

$\angle MKL = 41$

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

$NK = \frac{1}{2} * MK$

$NK = \frac{1}{2} * 30$

$NK = 15$

Solving (b): JL

JL is a diagonal, and it is twice of NL.

$JL = 2 * NL$

$JL = 2 * 13$

$JL = 26$

Solving (c): KL

To solve for KL, we consider triangle KNL where:

$\angle KNL = 90$

and

$KL^2 = NL^2 + NK^2$

$KL^2 = 13^2 + 15^2$

$KL^2 = 394$

$KL = \sqrt{394$

$KL = 19.85$

Solving (d - h):

To do this, we consider triangle JKN

$\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90$ -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

$\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41$

Similarly:

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41$

$\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49$

So:

$\angle JKM =49$

$\angle JML =41$

$\angle MLK = \angle MLJ + \angle JLK$

$\angle MLK = 49 + 41$

$\angle MLK = 90$

$\angle MNL =90$

$\angle KJL =41$

5 0

3 years ago

A circle has a radius of 6. An arc in this circle has a central angle of 330

sashaice [31]

Answer: $Arc\ lenght\approx34.55\ units$

Step-by-step explanation:

<h3> The complete exercise is: " A circle has a radius of 6. An arc in this circle has a central angle of 330 degrees. What is the arc length?"</h3><h3></h3>

To solve this exercise you need to use the following formula to find the Arc lenght:

$Arc\ lenght=2\pi r(\frac{C}{360})$

Where "C" is the central angle of the arc (in degrees) and "r" is the radius.

In this case, after analize the information given in the exercise, you can identify that the radius and the central angle in degrees, are:

$r=6\ units\\\\C=330$

Therefore, knowing these values, you can substitute them into the formula:

$Arc\ lenght=2\pi (6\ units)(\frac{330}{360})$

And finally,you must evaluate in order to find the Arc lenght.

You get that this is:

$Arc\ lenght=2\pi (6\ units)(\frac{11}{12})\\\\Arc\ lenght=11\pi \ units\\\\Arc\ lenght\approx34.55\ units$

3 0

3 years ago

Read 2 more answers

Henry wants some of his

Morgarella [4.7K]

Answer:

maybe 14 or 15 im not good with this stuff im in 8th grade and im very very behind a lot im prob gonna delete this app cuz I dont understand anything

3 0

3 years ago

Factorise fully 77x-33x^2

lesya [120]

Answer:

11x(7 - 3x)

Step-by-step explanation:

77x - 33x² ← factor out 11x from each term

= 11x(7 - 3x)

7 0

2 years ago