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Rzqust [24]
4 years ago
10

When energy is changed from one form to another, some of the energy is lost to the surroundings as waste thermal energy. The mor

e steps needed to arrive at the desired energy or the more types of energy that are generated, the more energy is wasted. Which object would likely have the least amount of wasted energy?
Chemistry
1 answer:
Nataly_w [17]4 years ago
8 0

<u>Full question:</u>

When energy is changed from one form to another, some of the energy is lost to the surroundings as waste thermal energy. The more steps needed to arrive at the desired energy or the more types of energy that are generated, the more energy is wasted.

Which object would likely have the least amount of wasted energy?

A) an electric drill

B) a solar cell

C) a car engine

D) a hydroelectric dam

Solar cell

<u>Explanation:</u>

In an electric drill, the conversion of electrical energy into mechanical energy takes place. Heat energy is obtained when the desired object gets broken with the drill.

In car engine, thermal energy is obtained from the chemical energy which in turn is converted into mechanical energy which is very essential for moving car.

In hydroelectric dam, energy is obtained from water that is stored in dam. The potential energy of water is transformed into mechanical energy which in turn is converted into kinetic energy which again is transformed into an electrical energy.

In the above methods the transformation of energy takes many steps wherein more amount of energy gets wasted.

In Solar cell, the energy that is obtained from the sun is directly converted into electrical energy. Hence, in solar cell, only less amount of energy will be wasted.

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Answer:

See Explanations....

Explanation:

NOTE => See attached graph.

1. 25-Turn Electromagnet

a. Strength of Batteries 1.5v vs 6.0v

6v:1.5v => 4:1 voltage ratio => That is, 6v battery is 4x voltage of 1.5v battery.

b. Ratio of Paperclips Picked Up

23clips(6v):6clips(1.5v) => 3.8clips(6v):1clip(1.5v)

That is, the 6 volt battery-EM picks up 3.8x more clips than the 1.5v battery-EM assuming constant number of coils given.

c. Empirical Relationship

From data given, an increase in voltage (V) produces a proportional increase in number of paperclips (C) picked up.  Such is a Direct Relationahip between #Clips Picked Up and Battery Voltage.

Thus, C ∝ V => C = kV => k = C/V

Therefore, for k₁ = k₂ => C₁/V₁ = C₂/V₂

2. 50-Turn Electromagnet

a. Ratio of turns between electromagnets.

50-Turn EM : 25-Turn EM => 2:1 ratio of turns between electromagnets

b. Ratio of Paperclips Picked UP

Between maximum voltage and minimum voltages for 50-Turn EM

=> 47 clips (6v) : 13 clips (1.5v) => 3.6:1 ratio...

That is, the 6v battery-EM, on the average, picks up 3.6x more clips than the 1.5v battery-EM given 50-Turn EM.

3. Doubling number of coils:

Doubling the number of coils, on the average, doubles the number of clips picked up by either electromagnet.

      Voltage              50-Turn EM      25-Turn EM     Pick Up Ratio

         1.5v                         13                       6                        2:1

         3.0v                        26                     12                        2:1

         4.5v                         31                    15.5                      2:1

         6.0v                         47                     23                      2:1  

4. Doubling Voltages:

Doubling voltage doubles the number of clips picked up by a given electromagnet regardless of the number of coils associated with magnet.

25-Turn EM          Voltage      Clips Pkd UP

                                1.5v                 6      

                                3.0v               12                

Double voltage => Doubles # clips picked up*

50-Turn EM          Voltage      Clips Pkd UP

                                1.5v                 13      

                                3.0v                26                

Double voltage => Doubles # clips picked up*

*Double Voltage => Double #clips picked up regardless of number of coil turns in electromagnet.

5.  Predicting number of clips for 7.5v battery-EM

Using linear trendline equations shown on attached graphs...

#clips 50-Turn EM = 7.1333V + 2.5 = 7.1333(7.5) + 2.5 ≅ 56 clips

#clips 25-Turn EM = 3.6333V + 0.5 = 3.6333(7.5) + 0.5 ≅ 27 clips

Overall => 2:1 ratio of clips between 50-Turn EM and 25-Turn EM

6. Slope values based upon trendline equations shown on attached graphs are ...

25 Turn EM => slope = 3.6333

50 Turn EM => slope = 7.1333

Approximately a 2x increase upon doubling the number of coils of electromagnet.

Predicting number of clips for 1V electromagnets:

#Clips (1volt) 25-Turn EM = 3.6333(1) + 0.5 = 3.6833 ≅ 4 clips

#Clips (1volt) 50-Turn EM = 7.1333(1) + 2.5 = 9.6333 ≅ 10 clips

Shows to be consistent with double #clips with double number of coil turns.

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