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charle [14.2K]
3 years ago
11

6.201cm+7.4cm+0.68 cm+12.0cm

Chemistry
1 answer:
zimovet [89]3 years ago
8 0
If you want the answer is centimeters is it going to be:
26.281 cm
If it make it easier for you to solve add 6.201 and 7.4 which will equal 13.601. Then add .68 to 13.601 which equals 14.281. Last add 12 to 14.281 which equals 26.281.

Hope this helps.

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Thermal energy _____ as temperature increases
Romashka-Z-Leto [24]
A. increases

As the temperature increases, the average kinetic energy of the particles in an object will increase. If the temperature of an object doesn't change, the thermal energy will increase as the mass of the object increases.

hope this helps <3
5 0
2 years ago
2 FONS
stiv31 [10]

Answer:

C. It decreases by a factor of 4

Explanation:

F1 = kq1*q2/r²

F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4)  = F1/4

7 0
3 years ago
Your boss tells you that water at 68 F is flowing in a cooling tower loop at a rate of 600 gpm, in an 8-inch inside diameter pip
avanturin [10]

Explanation:

The volumetric flow rate of water will be as follows.

       q = 600 gpm \times \frac{0.000063 m^{3} s^{-1}}{1 gpm}

         = 0.0378 m^{3}/s&#10;

    Diameter = 8 in \times \frac{0.0254 m}{1 in}

                   = 0.2032 m

Relation between area and diameter is as follows.

           A = \frac{\pi}{4} \times D^{2}

               = \frac{3.14}{4} \times (0.2032 m)^{2}

               = 0.785 x 0.2032 x 0.2032

               = 0.0324 m^{2}

Also,     q = A × V

or,         V = \frac{q}{A}

                = \frac{0.0378 m^{3}/s}{0.0324 m^{2}}

                = 1.166 m/s

As, viscosity of water = 1 cP = 10^{-3} Pa-s

Density of water = 1000 kg/m^{3}

Therefore, we will calculate Reynolds number as follows.

 Reynolds number = \frac{D \times V \times density}{viscosity}

                                 = \frac{0.2032 m \times 1.166 m/s  \times 1000}{10^{-3}}  

                                = 236931.2

Hence, the flow will be turbulent in nature.

Thus, we can conclude that the Reynolds number is 236931.2 and flow is turbulent.

8 0
3 years ago
During photosynthesis, plant leaves take in carbon dioxide through _______ in their leaves. a stomata b xylem c phloem
Iteru [2.4K]
<h3>Answer:</h3>

Stomata

<h3>Explanation:</h3>
  • Photosynthesis refers to the process that takes place in green plants and some algae.
  • During the process, water and carbon dioxide are converted to nutrients or organic compounds using energy from sunlight.
  • The process takes place in the chloroplast on the leaves of green plants.
  • The water used during photosynthesis comes from the soil and then transported by xylem tissue to the leaves where the process takes place.
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7 0
3 years ago
A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is The bomb had a heat c
gulaghasi [49]

Answer:

The enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

Explanation:

The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with this equation, and assuming no heat is lost to  the surroundings, we write :

qcal= Ccal × ΔT= 490 J/K × 276.7 K= <u>135,583 J</u> = 135.58 kJ

Note we expressed the temperature change in K, because the heat capacity is written in K.

<u> Now that we have the heat of combustion, we need to calculate the molar heat.  </u>

Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -135.58 kJ.

This is the heat released by the combustion of 4.40 g of ethanol ; therefore, we can write  the <u>conversion factor as 135.58 kJ/ 4.40 g</u>.

The molar mass of ethanol is 46.07 g, so the heat of combustion of 1 mole of ethanol is :

molar heat of combustion= -135.58 kJ/4.40 g x 46.07 g/ 1 mol= -1419.58 kJ/mol

Therefore, the enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

3 0
3 years ago
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